Question

How to solve this inequality

Answer 1

${x}^{2} + 16x - 16 > 0 \\ \\ x < - 4(2 + \sqrt{5} ) \\ x > - 4(2 - \sqrt{5}) \\ \\ x < - 8 - 4 \sqrt{5} \: or \: x > - 8 + 4 \sqrt{5}$

Answer 2

Answer:

x < -8 or x > 2

Explanation:

Find the critical points of the inequality.

Start by factoring the left side of the equation: (x - 2)(x + 8) = 0

Set your factors to equal zero: x - 2 = 0 or x + 8 = 0

x = 2 or x = -8

Check intervals between critical points. (Make sure to test your values to see if they work.)

x < -8 works in the original inequality. -8 < x < 2 doesn't work in the original inequality. x > 2 works as well.