To graph the line, we must first find out the equation for the line in slope-intercept form (y = mx + b). So far, we only have the slope, so the line's equation is y = 3/4x + b. But, by inserting the values of x and y in the point we know, we can find the y - intercept.
4 = 3/4 + b
b = 13/4
That means that the equation of our line is y = 3/4x + 13/4. Now we can graph. But, there is another way to go about (slightly faster too). Since we know the coordinates of 1 point, we can put that line down. Then, since we know that slope is rise over run, we can say, that with a slope of 3/4, one would go 3 points up for every 4 to the right. Now we can go 3 points up and 4 points to the right of point (1,4). That would be (5, 7). Now we can graph (since we have 2 points, or an equation).
The graph looks like this:
Answer:
Step-by-step explanation:
F(x) = x² - 2x + 1
= (x - 1)²
By comparing this equation with the vertex form of the quadratic equation,
y = (x - h)² + k
Here, (h, k) is the vertex
Vertex of the parabola → (1, 0)
x-intercepts → (x - 1)² = 0
x = 1
y-intercepts → y = (0 - 1)²
y = 1
Now we can draw the graph of the given function,
From this graph,
As x → 0,
f(0) = (0 - 1)²
= 1
Since,
Therefore, given function is continuous at x = 0.
Answer:
d =
Step-by-step explanation:
1) To solve for d, isolate it in the equation. So, to get rid of the with the d, add
to both sides.
Thus, d = .