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3 years ago

6

Find the volume of a right circular cone that has a height of 17.7 cm and a base with a diameter of 15.8 cm. Round your answer t

o the nearest tenth of a cubic centimeter.

2 answers:

kvasek [131]3 years ago

5 0

Answer:

1157.3cm^3

Step-by-step explanation:

voume of a cone =V=πr^2h^3

Diameter = 15.8cm

Height = 17.7cm

Radius = diameter/2

= 15.8/2 = 7.9cm

Pi = 22/7

V = 22/7 ×7.9×7.9×17.7/3

= 22/7×62.41×5.9

V = 1157.25cm^3

Hence the volume of the cone is 1157.3cm^3

to the nearest 10th

Lelu [443]3 years ago

3 0

Answer:

$1156.8cm^3$

Step-by-step explanation:

The volume of a cone is given as:

$V =\frac{1}{3} \pi r^2h$

where r = radius

h = height of cone

The height of the cone is 17.7 cm and its base radius is 7.9 cm (diameter is 15.8 cm).

Its volume is:

$V = \frac{1}{3} * \pi = 7.9^2 * 17.7\\ \\V = 1156.8cm^3$

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What value represents the number of ways in which the expected classes are free to vary in the chi-square goodness-of-fit test?

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In statistics, the number of degrees of freedom is the number of values in the final calculation of a statistic that are free to vary.

The number of independent ways by which a dynamic system can move, without violating any constraint imposed on it, is called number of degrees of freedom. In other words, the number of degrees of freedom can be defined as the minimum number of independent coordinates that can specify the position of the system completely.

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3 years ago

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Answer:

see below

Step-by-step explanation:

Part A

Since the lines goes through the point (0,0) the graph is proportional. We can find the rate of change by take the price of corn and dividing by the number of bushels

24/3 = 8 dollars/ bushel

Part B

Previous Year Number of Bushels Price of Corn (dollars)

3 21

6 42

9 63

12 84

We can find the rate of change for the previous year by using the slope formula

m = (y2-y1)/(x2-x1)

m = (84-63)/(12-9)

=21 / 3

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3 years ago

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How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

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Each A.U. has 149,59,7871 km.

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$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

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26% of 50
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