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Pachacha [2.7K]
2 years ago
14

Can someone help please

Mathematics
1 answer:
Anon25 [30]2 years ago
3 0

Answer:

x1.20

y0.75)

Step-by-step explanation:

you have to simplify

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Write an equation of the line with slope 2/3 that goes through the point -2,5
irinina [24]

Answer:

y = 2/3x + 19/3

Step-by-step explanation:

First, this is your current equation: y = 2/3x + b. Plug in your point to the equation, it should look like this: 5 = 2/3(-2) + b. 2/3 times -2 equals -4/3. So, this is what your equation should look like: 5 = -4/3 + b. Add 4/3 to both sides of the equation to get 19/3 = b. Go back to your original equation and plug 19/3 to b. This is your final equation: y = 2/3x + 19/3. Hope this helped!

7 0
2 years ago
What two numbers multiply to get -56 and add to get -1?
sukhopar [10]
It is -8 and 7.
-8 x 7 = -56.
-8 + 7 = -1

Hope This Helps You!
Good Luck Studying :)
4 0
3 years ago
Use the diagram below to answer the questions. Line q contains points J, K, and M. Point P is above line q between points K and
Flauer [41]

Answer:

2nd 3rd and last option

Step-by-step explanation:

2.

3.

6.

5 0
3 years ago
Read 2 more answers
A recipe calls for 2/5 cup of sugar for every 8 teaspoons of vanilla. What is the unit rate in teaspoons per cup ?
tamaranim1 [39]
For 2/5 cup, vanilla needed = 8 teaspoons
so, for 1 cup, it would be: 8 / 2/5
⇒8 × 5/2
⇒40/2
⇒20

In short, Your Answer would be 20 teaspoons

Hope this helps!
7 0
3 years ago
Read 2 more answers
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
3 years ago
Read 2 more answers
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