Answer:
<u>Step-by-step explanation:</u>
common ratio (r) =
first term (a₁) =
= a₁ (r)ⁿ⁻¹
=
Answer:
<em>Answer: Quadrant 4</em>
Step-by-step explanation:
<u>Graph of Functions
</u>
Let's analyze the function
To better understand the following analysis, we'll factor y
For y to have points in the first quadrant, at least one positive value of x must produce one positive value of y. It's evident that any x greater than 0 will do. For example, x=1 will make y to be positive in the numerator and in the denominator, so it's positive
For y to have points in the second quadrant, at least one negative value of x must produce one positive value of y. We need two of the factors that are negative. It can be seen that x=-2 will make y as positive, going through the second quadrant.
For the third quadrant, we have to find at least one value of x who produces a negative value of y. We only need to pick a value of x that makes one or all the factors be negative. For example, x=-4 produces a negative value of y, so it goes through the third quadrant
Finally, the fourth quadrant is never reached by any branch because no positive value of x can produce a negative value of y.
Answer: Quadrant 4
Answer:
B. (2, 2), (6, 4), (8, 10), (9, 28)
Step-by-step explanation:
I hope this helped! :D
I think the correct answer from the choices listed above is option C. The rem preimage does not describe polygon A'B'C'D'. The preimage is t<span>he original figure prior to a transformation. In the example below, the transformation is a rotation and a dilation. Hope this answers the question.</span>
Answer:
The sample has not met the required specification.
Step-by-step explanation:
As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow
: The true average penetration is 50 mils
: The true average penetration is > 50 mils
Since we are trying to see if the true average is greater than 50, this is a right-tailed test.
If the <em>level of confidence</em> is α = 0.05 then the score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)
The z-score associated with this test is
where
= <em>mean of the sample</em>
= <em>average established by the specification</em>
s = <em>standard deviation of the sample</em>
n = <em>size of the sample</em>
Computing this value of z we get z = 3.42
Since z > we can conclude that the sample has not met the required specification.