Answer:
wait what?
how is something meant to be due late, like b r u h you can't make a task due late. LOL :)
Step-by-step explanation:
Answer:
g(3) = 11
g(-3) = 16
g(-1) =3
Step-by-step explanation:
For g(3)
g(x)= x² +2
g(3) = 3² + 2
g(3) = 9+2
g(3) = 11
For g(-3)
g(x) = -3x + 7
g(-3) = -3(-3) + 7
g(-3) = 9 + 7
g(-3) = 16
For g(-1)
g(x) = x² + 2
g(-1) = (-1)² +2
g(-1) = 1+2
g(-1) =3
Answer:
Step-by-step explanation:
Given that Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is selected at random
the probability
(a) The student is enrolled in mathematics=
(b) The student is enrolled in English.=
(c) The student is enrolled in both.=
(d) The student is enrolled in mathematics or English.=
(e) The student is enrolled in English but not in mathematics.
=
(f) The student is not enrolled in English or is enrolled in mathematics.
=
Answer:
11(4h-3)
Step-by-step explanation:
The greatest known common factor of 44h and 33 is 11. So using the distributive property, I got 11(4h-3)
Answer:
Step-by-step explanation: