Answer:
where is the questions I don't know
Extraneous solutions, is answers that we get because of squaring both sides of the radical equation, but in reality, they are not going to be the solutions of the given equation.
(√(4x+41))²=(x+5)²
4x+41=x²+10x+25
x²+6x-16=0
(x-2)(x+8)=0
x1=2 , x2=-8,
And now we must to check them by substitution into initial equation
√(4x+41)=x+5
1) x=2, √(4*2+41)=2+5, √49=7, 7=7 true
2) x=-8, √(4*(-8)+41)=-8+5, √9 =-3 false,
so an extraneous solution x=-8
The answer is A
You would multiply the second equation by -2 to clear the 'y'.
This leaves -10x = 2B and 3x = A
When combining these we get -7x = A - 2B
The answer is c because a subtraction sign means less
Answer:
Step-by-step explanation:
x=
x=9 in.