Which equation, written in slope-intercept form, matches the graph below?

Mathematics

1 answer:

Vanyuwa [196]2 years ago

8 0

Y= -1/3x-4 (the first one)

You might be interested in

Help me with number 3 please

Harlamova29_29 [7]

The answer would be 22%

6 0

2 years ago

Diff Eq dy/dx= (ycos(x))/(1+y^2) initial condition is y(0)=1 work below ...?

Volgvan

Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2

5 0

3 years ago

How would you do this?

s344n2d4d5 [400]

Answer:

aileenessayhelp.com

7 0

3 years ago

Read 2 more answers

5=4b-12 hurry and make sure you put how you got the answer

PIT_PIT [208]

Answer:

4.25

Process:

5=4b-12
4b=12+5
4b=17
b= $\frac{17}{4}$
b= 4.25

5 0

2 years ago

Read 2 more answers

Find f (0) if f(t) = t2 – 2t – 5.

Sonbull [250]

Answer is -5.

Explanation- Since t equals 0. You put 0 in place of every t.

0(2)- 2(0)- 5 =
0-0-5= -5

8 0

3 years ago

Read 2 more answers