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maw [93]
3 years ago
11

For the function y = 3x2 - 12x + 4, what’s the mirror point for the y-intercept? Remember to type your point in the form (x,y) w

ithout any spaces.,
Mathematics
1 answer:
Serjik [45]3 years ago
6 0

Answer:

(4,4).

Step-by-step explanation:

First find the axis of symmetry:

y = 3x^2 - 12x + 4

y = 3(x^2 - 4x) + 4

y = 3 [(x - 2)^2 - 4] + 4

y = 3(x - 2)^2 - 8

So the axis of symmetry is x = 2.

The y intercept of the function y is where x= 0 and y = 4  - that is (0,4).

The mirror point for the y intercept is the reflection  of (0,4) in the line x = 2.

That is  (2*2, 4) = (4,4).

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