Let the height of the building be x. Let the initial distance of the ant from the building be y, then
tan 32 = x/y
y = x/tan 32 . . . . . . . . (1)
tan 22 = x/(y + 66)
y tan 22 + 66 tan 22 = x
y = (x - 66 tan 22)/tan 22 . . . . . . . . (2)
Equating (1) and (2), we have
x/tan 32 = (x - 66 tan 22)/tan 22
x tan 22 = x tan 32 - 66 tan 22 (tan 32)
x(tan 32 - tan 22) = 66 tan 22 (tan 32)
x = (66 tan 22 (tan 32))/(tan 32 - tan 22) = 66(0.4040)(0.6249)/(0.6249 - 0.4040) = 16.6626/0.2208 = 75.4
Therefore, the height of the building is 75.4 feet.
Answer:
2
+7x-15
Step-by-step explanation:
I presume f(x)=x+5 and g(x) =2x-3 and the question is f(x)*g(x)
f(x)*g(x)
(x+5)(2x-3)
distribute
2+10x-3x-15
2+7x-15
Answer:
t = 610
Step-by-step explanation:
668 - 58 = 610
610 + 58 = 668
Answer:
5x-20=3x(alternate angle)
5x-3x=20
2x=20
x=20/2
x=10
now ,
2y +4y+5x-20=180(sum of angles of a triangle)
6y+50-20=180
6y+30=180
6y=180-30=150
y=150/6
y=25
hope this will help
A=L×W
1)Area of walkway
4×12=48
2)Area of stone
2×2=4
3)Divide
48÷4=12
12 stones
