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Scrat [10]
4 years ago
13

A garden snail moves 1/6 foot in 1/3 hours. what is the unit rate?

Mathematics
2 answers:
fiasKO [112]4 years ago
8 0
1 hour=1/6+1/6+1/6
1 hour=3/6
1 hour=1/2

for every hour, the snail moved 1/2 a foot
Kazeer [188]4 years ago
3 0
The answer is:  "1.2 ft. / h " ;  or, write as:  "0.5 ft. / h" .
________________________________________
To calculate the unit rate:
_______________________________________
{(1/6) ÷ (1/3)] ft/hr .
_______________________________________
Note:
_______________________________________
{(1/6) ÷ (1/3)] = {(1/6) * (3/1)]}  = (1*3) / (6*1) = 3/6 = (3÷3)/(6÷3) ;
                                                
                                            = 1/2 ; or 0.5.
________________________________________
The answer is:  "1.2 ft. / h " ;  or, write as:  "0.5 ft. / h" .
________________________________________
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Given the coordinate transformation f(x, y) = (- 2x, y) and the domain (0, 5), (8, - 1) and (- 6, 4) what is the range?
Mariana [72]

Answer:

{(0, 5), (-16, -1), (12, 4)}

Step-by-step explanation:

Given the coordinate transformation f(x, y) = (- 2x, y) and the domain (0, 5), (8, - 1) and (- 6, 4), to get the range, we will get f(x, y) for all the domain values

For the coordinate (0,5);

f(0, 5) = (-2(0), 5)

f(0, 5) = (0, 5)

For the coordinate (8, -1);

f(8, -1) = (-2(8), -1)

f(8, -1) = (-16, -1)

For the coordinate (-6, 4);

f(-6, 4) = (-2(-6), 4)

f(0, 5) = (12, 4)

Hence the range is {(0, 5), (-16, -1), (12, 4)}

5 0
3 years ago
Given the complex number z_1=3\big(\cos \frac{14\pi}{15} +i\sin \frac{14\pi}{15}\big)z 1 ​ =3(cos 15 14π ​ +isin 15 14π ​ ) and
mars1129 [50]

The product of <em>z₁ =</em> 3 · (cos 14π/15 + i · sin 14π/15) and <em>z₂ =</em> 3 √3 · (cos 11π/15 + i · sin 11π/15) in <em>rectangular</em> form with fully simplified expressions is <em>z₁ · z₂ =</em> 7.794 - i · 13.5.

<h3>How to determine the product of two complex numbers</h3>

Let be two numbers of the form <em>z = a + i · b</em>, where <em>i =</em> √-1, the product of two of these numbers in <em>rectangular</em> form is described by the following formula:

<em>z₁ · z₂ = (a + i · b) · (c + i · d) = (a · c - b · d) + i · (a · d + b · c)</em>   (1)

If we know that a = 3 · cos 14π/15, b = 3 · sin 14π/15, c = 3√3 · cos 11π/15, d = 3√3 · sin 11π/15, then the result in rectangular form is:

<em>z₁ · z₂ =</em> 7.794 - i · 13.5

The product of <em>z₁ =</em> 3 · (cos 14π/15 + i · sin 14π/15) and <em>z₂ =</em> 3 √3 · (cos 11π/15 + i · sin 11π/15) in <em>rectangular</em> form with fully simplified expressions is <em>z₁ · z₂ =</em> 7.794 - i · 13.5. \blacksquare

<h3>Remark</h3>

The statement presents typing mistakes and is poorly formatted, the correct form is introduced below:

<em>Given the complex number z₁ = 3 · (cos 14π/15 + i · sin 14π/15) and z₂ = 3 √3 · (cos 11π/15 + i · sin 11π/15), express the result of z₁ · z₂ in rectangular form with fully simplified fractions and radicals.</em>

<em />

To learn more on complex numbers, we kindly invite to check this verified question: brainly.com/question/10251853

8 0
2 years ago
At what x value does the function given below have a hole?<br><br> f(x)=x+3/x2−9
S_A_V [24]

Answer:

hole at x=-3

Step-by-step explanation:

The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)

The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.

So anyways we have (x+3)/(x^2-9)

= (x+3)/((x-3)(x+3))

Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.

4 0
3 years ago
Find the length of a side of a square if its área is 4/25 cm2
USPshnik [31]

Answer:

2/5cm or 0.4cm

Step-by-step explanation:

Area of square = Side^{2}

Thus, Side = \sqrt{Area}

= \sqrt{4/25}

= 2/5 cm = 0.4cm

4 0
3 years ago
Emily thinks the perfect tomato sauce has 8 cloves of garlic in every 500{ mL} of sauce. Raphael's tomato sauce has 12 cloves of
igomit [66]

For perfect solution we need to have :-  8 colves   in 500ml    solution

500   ml     has   8 cloves

1 ml             has     8 / 500 cloves

100ml         has   8 / 500  * 100  =    8/5  = 1.6 cloves

Raphael's mixture  

    900 ml  has 12 cloves

      1 ml     has   12 / 900 cloves

   100 ml has   12 / 900 *  100   =    12 / 9  =   1.33 cloves

so concentration of garlic in 100 ml solution of Raphael's solution is less than Emily's solution    so it is not garlicky enough.     ( option B)

5 0
3 years ago
Read 2 more answers
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