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Andrej [43]
3 years ago
7

In an arithmetic series, the terms of the series are equally spread out. For example, in 1 + 5 + 9 + 13 + 17, consecutive terms

are 4 apart. If the first term in an arithmetic series is 3, the last term is 136, and the sum is 1,390, what are the first 3 terms? A. 3, 10, 17 B. 3, 23, 43 C. 3 , 36.333 , 70 D. 3, 69.5, 136 2 E. 3, 139, 1,251
Mathematics
1 answer:
sertanlavr [38]3 years ago
4 0
Sn = n/2(a + l); where sn is the sum of n terms, n is the number of terms, a is the first term and l is the last term.

1390 = n/2(3 + 136)
2780 = 139n
n = 2780/139 = 20

2nd term = 3 + 20 = 23
3rd term = 23 + 20 = 43

First three terms = 3, 23, 43

option b.
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A recipe uses 214 cups of flour for a batch of cookies. Henry makes 10 batches of cookies for a bake sale.
yanalaym [24]

Answer:

Step-by-step explanation:

A recipe uses 214 cups of flour for a batch of cookies. Henry makes 10 batches of cookies for a bake sale.

A model shows a total of c cups divided into 10 sections, each labeled 2 and 1 fourth.

Part A

Which equation models the total number of cups of flour, c, Henry needs?

c+214=10

214×c=10

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214×10=c

Part B

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Part C

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3 years ago
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Answer:

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