Answer:
X=5/7
Step-by-step explanation:
See answer above pls____
It's 21 square units. If you map it on a complex plane (x-axis is real numbers, y-axis is imaginary numbers) you'll see that the sides of the rectangle is 3 and 7 which multiply to 21.
(a) First find the intersections of
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and
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:
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So the area of
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is given by
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If you're not familiar with the error function
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, then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.
(b) Find the intersections of the line
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with
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.
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So the area of
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is given by
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
which is approximately 1.546.
(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve
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and the line
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, or

. The area of any such circle is

times the square of its radius. Since the curve intersects the axis of revolution at

and
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, the volume would be given by
Answer:
We can graph y = 2x/3 - 2 to find the line.
We know one point, which is the y-intercept. The y-intercept is (0,-2) so that is our first point. Plot that point on the chart. Now to find another point, we can just insert a number for x and solve for y. I am going to use the number 3.
y = 2x/3 - 2
y = 2(3)/3 - 2
y = 6/3 - 2
y = 2 - 2
y = 0
So when x = 3 y = 0. We have another point,which is (3,0) Plot the points (0, -2) (3, 0) and draw a line between the points and that is your graph.
there ya go