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4 years ago

Based on the specificity and reversibility principle, training during the off-season should?

Business

1 answer:

likoan [24]4 years ago

6 0

Answer:

Off-season training should be focused on building general strength and conditioning in activities that are similar to the sport an athlete. According to the principle of specificity and reversibility, specificity states that the change in physical nature of the body is in line with the training type performed. Reversibility explains how an athlete can lose the effects gained from training from he stops training. Thus to stay fit, off-season training must concentrate on exercises that keeps the body in shape for the same type of sports.

Explanation:

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Janet, a manager at hollyoak systems, is known for her passionate and people-friendly ways. janet knows all her employees well a

PtichkaEL [24]

Based on the scenario above, Janet can be regarded as an Free-rein learder. Janet has the authority style where subordinates are not straightforwardly managed and rather should work on possess and demonstrate their value through achievements. No particular supervisory criteria must be met.

3 0

3 years ago

Read 2 more answers

Instead of assigning access for each user account individually, ________ is a more efficient and easier-to-manage approach. Cent

katovenus [111]

Answer:

Role-Based Access Control (RBAC)

Explanation:

Instead of assigning access for each user account individually, Role-Based Access Control (RBAC) is a more efficient and easier-to-manage approach.

In computer systems security, role-based access control or role-based security is an approach to restricting system access to authorized users. It is used by the majority of enterprises with more than 500 employees, and can implement mandatory access control or discretionary access control.

Hence, access need not be assigned for each user individually.

4 0

3 years ago

When the expected inflation rate increases, the real cost of borrowing ________ and bond supply ________, everything else held c

Dafna1 [17]

Answer:

The answer is: C) decreases ; increases

Explanation:

The real cost of borrowing is calculated by adjusting the nominal cost of borrowing by the inflation rate. This means that if the inflation rate increases, then the adjusted real cost of borrowing will decrease.

The inflation rate increases when country´s money supply growth rate outpaces its economic growth. So when the inflation rate increases (lowering the real cost of borrowing), borrowers are more likely to issue bonds, increasing the bond supply.

4 0

3 years ago

Based on the following information, prepare the bank reconciliation for Cougar Corp. as of December 31. A. On December 31, Couga

True [87]

Answer and Explanation:

The Preparation of bank reconciliation for Cougar Corp. as of December 31 is shown below:-

Cougar Corp.

Bank reconciliation

For the year ended December 31

Particulars Amount

Bank balance Dec 31 $24,575

Add: Deposit in transit $2,500

Less:

Outstanding checks #302 ($180)

Outstanding checks #303 ($95)

Outstanding checks #304 ($25) ($300)

Bank balance adjusted $26,775

Cash balance on 31 Dec $26,504

Add: EFT from customer $1,700

Add: Interest income $21 $1,721

Less: Posting error

($5,400 - $4,500) $900

Less: NSF check $500 $1,400

Book balance adjusted $26,775

Hence, the bank balance and the book balance are matched

8 0

3 years ago

Repair calls are handled by one repairman at a photocopy shop. Repair time, including travel time, is exponentially distributed,

wolverine [178]

Answer:

the average number of customers awaiting repairs = 0.30

the system utilization = 42

the amount of time that the repairman is not out on a call is = 4.64 hours

the probability of two or more customers in the system = 0.1764

Explanation:

Given that :

Repair time, including travel time = mean of 1.6 hours per call.

Requests for copier repairs = mean rate of 2.1 per eight-hour day

i.e mean rate R = 2.1/day

Time = 8 hours

thus; mean rate μ = 8 hours/ 1.6 hours = 5

(a)

Let the average number of customers awaiting repairs be $I_i$ :

$I_i = \dfrac{R^2}{\mu (\mu-R)}$

$I_i = \dfrac{2.1^2}{5 (5-2.1)}$

$I_i = \dfrac{4.41}{5 (2.9)}$

$I_i = \dfrac{4.41}{14.5}$

$\mathbf{I_i = 0.30}$

the average number of customers awaiting repairs = 0.30

(b) Determine system utilization.

The system utilization is determined as follows:

$\delta = \dfrac{R}{\mu}$

$\delta = \dfrac{2.1}{5}$

${\delta = 0.42}$

$\mathbf{\delta = 42}$

Percentage of Idle time = 1 - $\delta$

Percentage of Idle time = 1 - 0.42

Percentage of Idle time = 0.58

However during an 8 hour day; The amount of time that the repairman is not out on a call is = 0.58 × 8 = 4.64 hours

(d)

the probability of two or more customers in the system by assuming Poisson Distribution is:

P(N ≥ 2) = 1 - (P₀+ P₁)

where;

P₀ = 0.58

P₁ = 0.58 × 0.42 = 0.2436

P(N ≥ 2) = 1 - ( 0.58 + 0.2436)

P(N ≥ 2) = 1 - 0.8236

P(N ≥ 2) = 0.1764

Thus; the probability of two or more customers in the system is 0.1764

7 0

4 years ago