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nlexa [21]
3 years ago
5

Write each mixed number as an improper fraction.4 3/5, 2 1/2,3 4/9,2 5/7

Mathematics
2 answers:
alisha [4.7K]3 years ago
8 0

23/5, 5/2, 31/9, and 19/7

All you have to do is multiply the whole number by the denominator and add the numerator. For example:

5 3/6 5*6 is 30 +6 is 36

therefore the improper fraction is 36/6 

Gnoma [55]3 years ago
7 0
23/5, 5/2,31/9,19/7 is the answer to ur question
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The Sample space for three cards is

S=\left\{\left(B,1\right),\left(R,1\right),\left(G,1\right),\left(B,2\right),\left(R,2\right),\left(G,2\right),\left(B,3\right),\left(R,3\right),\left(G,3\right),\left(B,4\right),\left(R,4\right),\left(G,4\right)\left(B,5\right),\left(R,5\right),\left(G,5\right),\left(B,6\right),\left(R,6\right),\left(G,6\right) \right \}

There are two cards red(R) and black(B) and a six-sided die.

The event is one card is picked randomly and then rolls the die.

So, the Sample space is as follows.

S=\left\{\left(B,1\right),\left(R,1\right),\left(B,2\right),\left(R,2\right),\left(B,3\right),\left(R,3\right),\left(B,4\right),\left(R,4\right),\left(B,5\right),\left(R,5\right),\left(B,6\right),\left(R,6\right) \right \}

<h3>Find Sample space if there are three cards.</h3>

Consider there were three cards red(R), black(B) and green(G) a six-sided die.

The event is one card is picked randomly and then rolls the die.

So, the sample space will be as follows,

S=\left\{\left(B,1\right),\left(R,1\right),\left(G,1\right),\left(B,2\right),\left(R,2\right),\left(G,2\right),\left(B,3\right),\left(R,3\right),\left(G,3\right),\left(B,4\right),\left(R,4\right),\left(G,4\right)\left(B,5\right),\left(R,5\right),\left(G,5\right)\left(B,6\right),\left(R,6\right),\left(G,6\right) \right \}.

Learn more about sample space here :-

brainly.com/question/24273864

#SPJ1

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