Answer:
A and B are both 3.
Step-by-step explanation:
The given polynomial is 
.
We factor the GCF to obtain:
We factor further by grouping to get:
![3x[x^2(x-6)+3(x-6)]](https://tex.z-dn.net/?f=3x%5Bx%5E2%28x-6%29%2B3%28x-6%29%5D)
We compare this to the given factored expression:
We must have A=3,B=3, C=-6
The value of given expression when x=-4 and y=4 is 1250.
The expression is missing in the question which is 
.
We have to solve it for x= -4 and y = 4.
Now putting the value of x and y we get,
Hence the value of given expression when x=-4 and y=4 is 1250.
For more details follow the link:
brainly.com/question/11897796
Ur gonna have to pick an equation and solve for a variable.
2x - 2y = 6
2x = 2y + 6 ...divide everything by 2 because u want x by itself
x = y + 3
now we sub y + 3 in for x in the other equation
14x - 2y = 78
14(y + 3) - 2y = 78...distribute thru the parenthesis
14y + 42 - 2y = 78...subtract 42 from both sides, cancelling the 42 on the left
-42 -42
-----------------------
14y - 2y = 36 ...simplify
12y = 36...divide by 12 on both sides, cancelling out the 12 on the left
y = 36/12
y = 3
now , we already know that x = y + 3...and we know y = 3...so sub in 3 for y and solve for x
x = y + 3
x = 3 + 3
x = 6
solution is (6,3)
it is always a good idea to check ur answer by subbing it into one or both of the equations to see if it is correct
2x - 2y = 6......(6,3)...x = 6 and y = 3
2(6) - 2(3) = 6
12 - 6 = 6
6 = 6 (correct)
so yes, ur solution is (6,3)
Answer:
m = (ps - b - uxs/t) / ux/t - p
Step-by-step explanation:
ux/t +b/m+s =p
multiplying throughout by (m+s) we get:
ux/t(m+s) + b = p(m+s)
open the brackets:
uxm/t + uxs/t + b = pm + ps
bring on one side of the equal sign all terms containg m, to make it the subject:
m(ux/t - p) = ps - b - uxs/t
m= (ps - b - uxs/t) / ux/t - p
Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
The other parameters are given as follows:
Hence, the lower bound of the interval is:
The lower limit of the 95% confidence interval is of $99,002.
More can be learned about the z-distribution at brainly.com/question/25890103
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