F is 198.374 hoped i helped
I’m pretty sure the answer is 30!
<span>Given that the orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P = a^(3/2).
If Saturn’s orbital period is 29.5 years, then
29.5 = a^(3/2)
a = (29.5)^(2/3) = 9.547
Therefore, Saturn's distance from the sun is 9.547 astronomical units.</span>
The answer is 3√5. You use the distance formula: √((x2-x1)^2+(y2-y1)^2)