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3 years ago

OKAY SO I HAVE 3 QUESTIONS THAT I NEED HELP WITH

Mathematics

2 answers:

Hunter-Best [27]3 years ago

8 0

1. 50c/1d

2. -4i/1w

3. 6/r+5/b= total cost

LiRa [457]3 years ago

7 0

1)
50 cupcakes per day
c = 50×d

2)
4in per week
i = 4 x w

3)
cost = 6×r + 5×b

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Evaluate t (-4). T(z)=z-6

jekas [21]

Simply plug -4 in for z in the equation. The result should give you T(z)=(-4)-6=-10
Notice -4 takes z spot

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3 years ago

Find the distance between the points (2, -9) and (-1, 4).

ollegr [7]

Answer:

A. 13.34

Step-by-step explanation:

This is the formula d=√((x_2-x_1)²+(y_2-y_1)²)

Plug in

d=√(-1-2)² + (4+9)²

d= √9 + 169

d= √178

d= 13.34

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3 years ago

hey! please help with this!!! Write all the 12 answer of measurements. If you can’t do it and you think it’s a lot you don’t hav

jarptica [38.1K]

Answer:

1) 1 and 4

2) 1 and 2

3) 1 and 5

4) 2 and 3

5) 130

6) 90

7) 25

8) 115

9) 70

10) 115

11) 40

12) 105

Step-by-step explanation:

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4 0

3 years ago

What is the distance from the sun to mercury in scientific notation

defon

57910000 kilometer
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(57.91 *10^6) k.m
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7 0

3 years ago

Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2

kotykmax [81]

Answer:

$2\frac{1}{6}\approx 2.167$ units.

Step-by-step explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

$\text{Total distance walked by Joy in 3 days}=3\times\frac{1}{3}+\frac{1}{2}+\frac{2}{3}$

$\text{Total distance walked by Joy in 3 days}=\frac{1*3}{3}+\frac{1}{2}+\frac{2}{3}$

Let us have a common denominator.

$\text{Total distance walked by Joy in 3 days}=\frac{3*2}{3*2}+\frac{1*3}{2*3}+\frac{2*2}{3*2}$

$\text{Total distance walked by Joy in 3 days}=\frac{6}{6}+\frac{3}{6}+\frac{4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{6+3+4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{13}{6}$

$\text{Total distance walked by Joy in 3 days}=2\frac{1}{6}$

Therefore, Joy traveled $2\frac{1}{6}\approx 2.167$ units in 5 days.

8 0

4 years ago