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Elden [556K]
4 years ago
9

Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2

1 x on 2/3
Mathematics
1 answer:
kotykmax [81]4 years ago
8 0

Answer:

2\frac{1}{6}\approx 2.167 units.

Step-by-step explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

\text{Total distance walked by Joy in 3 days}=3\times\frac{1}{3}+\frac{1}{2}+\frac{2}{3}

\text{Total distance walked by Joy in 3 days}=\frac{1*3}{3}+\frac{1}{2}+\frac{2}{3}

Let us have a common denominator.

\text{Total distance walked by Joy in 3 days}=\frac{3*2}{3*2}+\frac{1*3}{2*3}+\frac{2*2}{3*2}

\text{Total distance walked by Joy in 3 days}=\frac{6}{6}+\frac{3}{6}+\frac{4}{6}

\text{Total distance walked by Joy in 3 days}=\frac{6+3+4}{6}

\text{Total distance walked by Joy in 3 days}=\frac{13}{6}

\text{Total distance walked by Joy in 3 days}=2\frac{1}{6}

Therefore, Joy traveled 2\frac{1}{6}\approx 2.167 units in 5 days.

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