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3 years ago

A real number between the square root of 13 and square root of 14

Mathematics

1 answer:

Mice21 [21]3 years ago

5 0

3.65 would be a real number between sqrt 13 and sqrt 14

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the first week she earned 3 times as much as she earned the second week.The second week she earned twice as much as she earned t

ser-zykov [4K]

$6.

You can get this by dividing the original number by 3 and then the new answer by 2.

5 0

3 years ago

Do this for me pls its mdths

Vadim26 [7]

Answer:

A = -1

B = -3

C = -7

Step-by-step explanation:

See attached image.

5 0

2 years ago

BRAINLIEST TO CORRECT QUICKLY

Pani-rosa [81]

Answer:

-6 3/8 < -7/8

Step-by-step explanation:

Answer:

-6 3/8 < -7/8

Showing Work

Using the given inputs:

-6 3/8 -7/8

Rewriting these inputs as improper fractions:

-51/8 and -7/8

Since we have like denominators we compare the inputs by the numerators:

Therefore, comparison shows:

-6 3/8 < -7/8

8 0

3 years ago

Read 2 more answers

PLEASE I NEED HELP THX :) <3

SVETLANKA909090 [29]

Answer: 5/2

Step-by-step explanation:

Plug in two points from the table into the formula y2-y1 divided by x2-x1

I hope this helps.

6 0

3 years ago

The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a

horrorfan [7]

Answer:

Assuming population data

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$s = \sqrt{0.000425}=0.0206$

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

$\mu = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}$

And we got $\sigma^2 =0.000354$

And the deviation would be just the square root of the variance:

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$\bar X = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}$

And we got $s^2 =0.000425$

And the deviation would be just the square root of the variance:

$s = \sqrt{0.000425}=0.0206$

6 0

3 years ago