Answer:
A ; 23rd century
Step-by-step explanation:
Here, we want to select which of the options is next to have a descending year.
Since all are in the same century i.e 20-something, we do not have an issue with the first digit.
What we need to work on is the last three digits;
We can have 2210, we can have 2321, we can have 2432, we can also have 2543 and so on.
The most recent of all these is the year 2210, so what century does this belong?
Kindly note that, the years 2001-2100 belong to the 21st century.
The years 2101-2200 belong to the 22nd century while the years 2201-2300 belong to the 23rd century
The year we are looking to place is the year 2201 and thus belongs to between 2201-2300 which is the 23rd century
2c -7 >= 9
2c >= 16
c >= 8
5d + 7 <= 32
5d <= 25
d <= 5
normal arthematic except diving over -1 or flipping (taking inverse -1) flips the operator
Answer:
$16
Step-by-step explanation:
Round : $80.36 : $80
Equation : 20% of 80
Answer : $16
Sidenote: I hope this answers your questions!
Cos<span> 42° ~ 0.743
cos 42° = sin(90-42) = sin 58°
So sine of complementary angle also has same value as cos 42.
So sin 58 ~ 0.743
</span>
The values of the letters in coordinates (a, b) and (c,d) are;
<u><em>a = -4</em></u>
<u><em>b = -6</em></u>
<u><em>c = 2</em></u>
<u><em>d = 6</em></u>
<u><em /></u>
We are given two equations;
-6x + 3y = 6 ---(eq 1)
x² + y = 10 ---(eq 2)
- We are told that they intersect at coordinates; (a, b) and (c, d).
Let us make y the subject in eq 2 to get;
y = 10 - x² --(eq 3)
- Let us put 10 - x² into eq 1 to get;
-6x + 3(10 - x²) = 6
expanding further gives;
-6x + 30 - 3x² = 6
rearranging gives;
3x² + 6x - 24 = 0
Using online quadratic equation <em>solver</em>, we have;
x = -4 and x = 2
Putting x = -4 into eq 3 gives;
y = 10 - (-4)²
y = 10 - 16
y = -6
Putting x = 2 into eq 3 gives;
y = 10 - (2)²
y = 10 - 4
y = 6
- Thus, the coordinates are; (-4, -6) and (2, 6)
Comparing with (a, b) and (c,d), we have;
a = -4
b = -6
c = 2
d = 6
Read more at; brainly.com/question/15165519
