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2 years ago

Passing through (5, -4) and parallel to the line whose equation is y=-2x+3; point-slope form

Mathematics

1 answer:

Marina CMI [18]2 years ago

8 0

The answer is y=-2x+6

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Un tanque de 60 litros de agua se llenó solo hasta los 3 quintos de su capacidad ¿cuántos litros de agua hay en el tanque?

Romashka [77]

180 litros de agua en el tanque

3 0

2 years ago

What is the simplified form of the expression? k3 [k^7/3] -5

iragen [17]

Simplify the following:
(k^3 k^7)/3 - 5

Combine powers. (k^3 k^7)/3 = k^(7 + 3)/3:
k^(7 + 3)/3 - 5

7 + 3 = 10:
k^10/3 - 5

Put each term in k^10/3 - 5 over the common denominator 3: k^10/3 - 5 = k^10/3 - 15/3:
k^10/3 - 15/3

k^10/3 - 15/3 = (k^10 - 15)/3:
Answer: (k^10 - 15)/3

3 0

2 years ago

lol Barney has 16 1 yards of fabric. To make an elf costume, he needs 5 5 2 yards of fabric. How many costumes can Barney make?

ioda

Well i happen to have that question and it is that he has 16 1/5 fabric and need 5 2/5 to make an elf costume. how many costumes can he make? Well so basically all you have to do is 16 1/5 divided by 5 2/5, which is: 3. The answer is 3 hope this helped!

7 0

2 years ago

If 1/5 of the remaining blueberries is used to make muffins how many pounds of blueberries are left in the container

nlexa [21]

Answer:

4/5.

Step-by-step explanation:

would you mind looking at my question :)

3 0

2 years ago

Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

$V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3$

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

$0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L$

1.25 liters of oil are needed.

6 0

2 years ago