(2^8 x 3^-5 x 6^0) x [(3^-2/2^3) x 2^28] = x
(256 x .004 x 1) x [(.111/8) x 268,435,456] = x
(1.024 x 1) x .(0138 x 268,435,456) = x
1.024 x (.0138 x 268,435,456) = x
1.024 x 3,704,409.2928 = x
3,793,315.1158272 = x
Correct me if I am wrong. :)
Answer:
61
Step-by-step explanation:
to calculate the 20th term you use the formula
Tn=a+(n-1)d where a stands for the first term,n the number of terms and d the common difference.in this case the first term is 4 the common difference is 3 cause they were adding 3 to go to the next term.. therefore the solution will be:
Tn=4+(20-1)3
=4+19×3
=4+57
=61
the 20th term is 61
I hope this helps
Answer:
15, 30, 60, 120, 240, <u>480</u>.
Step-by-step explanation:
You multiply the numbers by 2 to get to the next number.
For example, 15*2 is 30. 30*2 is 60. 60*2 is 120, etc..
Answer:
f/c
Step-by-step explanation:
it is bcs 913/4 and the same concept is used
