Answer:
f^-1(x) = 4x^2 -3 . . . . x ≤ 0
Step-by-step explanation:
Interchange x and y, then solve for y.
x = -1/2√(y+3)
-2x = √(y +3)
4x^2 = y +3
4x^2 -3 = y
Note that the range of the function f(x) is f(x) ≤ 0, so this will be the domain of the inverse function. Then the inverse function is ...
f^-1(x) = 4x^2 -3 . . . . for x ≤ 0
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The attached graph shows this inverse function is a reflection of the function across the line y=x, as it should be.
The equation of the asymptote is
Explanation:
The given equation is
We need to determine the horizontal asymptote of the equation.
The given equation is of the exponential function of the form and has a horizontal asymptote
Hence, from the above equation, the value of k is 1.
Therefore, we have,
Thus, the horizontal asymptote is
Therefore, the asymptote of the equation is
If you subtract 2x from each side you get 5x-0.15=0.6 because the subtraction of 2x on the right of the equal sign cancels out. Then, if you add 0.15 to both sides you will get 5x=0.75. Finally, if you divide both sides by 5 you get x = 0.15.
Need to know the angle for this I think?