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Ivenika [448]
3 years ago
13

Somebody PLEASE HELP ME I DONT KNOW WHICH ONE IS THE ANSWER A, B,C,D

Mathematics
1 answer:
Leona [35]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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Write an expression to represent:<br> Eight more than the product of two and a number number x
NARA [144]
Eight more than the product of two and a number x

8+2x <== in mathematical form

Eight more= 8+

Product= multiply

number=x

~'Manda
7 0
3 years ago
Your closet has 5 shirts for every 4 sweaters. Your closet has 15 shirts. How many sweaters are in your closet?
Mnenie [13.5K]
Since it is a 5:4 it would be 15:12
3 0
2 years ago
Read 2 more answers
Jessica had 140 to spend on 8 books. After buying them she had 12 dollars. How much did each book cost?
Rashid [163]

Answer:

each book was $16

Step-by-step explanation:

140-12=128 divided by 8 = 16

hope this helps!

8 0
2 years ago
Which expression is equivalent to (x^4/3 x^2/3)^1/3?
KATRIN_1 [288]

Answer: x^{\frac{2}{3} }

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

(x^{a})(x^{b}) = x^{a + b} <em>(Exponents with the same base that are being multiplied together can have the exponents added)</em>

(x^{a})^{b} = x^{(a)(b)} <em>(A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)</em>

<em />

Let's apply it!

First, let's simplify what's inside the parenthesis.

x^{\frac{4}{3} } x^{\frac{2}{3} } <em>(Remember, they have the same base of "x", so we can add the exponents)</em>

x^{\frac{4}{3} + \frac{2}{3} } = x^{\frac{6}{3} } = x^{2}

Now we have (x^{2})^{\frac{1}{3} }. Let's use the second rule.

(x^{2})^{\frac{1}{3} } = x^{\frac{2}{3} }

Hope this helps! :^)

7 0
3 years ago
given the following information about two loaded die, what is the p(5) on die 2? die 1p(1) = 0.5 p(4) = 0.25 p(6) = 0.25 die 2p(
bagirrra123 [75]

Answer:

0.45

Step-by-step explanation:

Die 1 is loaded so that only 1, 4, and 6 are possible.

P(1) + P(4) + P(6) = 0.5 + 0.25 + 0.25 = 1

Similarly, Die 2 is loaded so that only 2, 3, and 5 are possible.

P(2) + P(3) + P(5) = 1

0.3 + 0.25 + P(5) = 1

P(5) = 0.45

3 0
2 years ago
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