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pychu [463]
2 years ago
5

The graph of an absolute value function contains the points (–3, 5), (0, 2) and (3, 5). Which could be the function represented

by this graph? Check all that apply.
f(x) = |x| + 2
f(x) = –|x| + 2
f(x) = |x| – 2
f(x) = |–x + 2|
f(x) = |–x| + 2
f(x) = –|x| – 2
f(x) = |x + 2|
Mathematics
1 answer:
Alex73 [517]2 years ago
4 0

The absolute value functions that contains the points are:

  • f(x) = |x| + 2
  • f(x) = |-x| + 2

<h3>Which could be the function represented by this graph?</h3>

Here we have the points (-3, 5), (0, 2), and (3, 5). We want to see which ones of the given functions have that points.

To check that, we need to evaluate the functions in the first value of each point and see if the outcome is the second value of the correspondent point.

For example, for the first equation:

  • f(-3) = |-3| + 2 = 5   so it has the point (-3, 5)
  • f(0) = |0| + 2 = 2  so it has the point (0, 2)
  • f(3) = |3| + 2 = 5  so it has the point (3, 5).

The other option that also contains these 3 points is:

f(x) = |-x| + 2

  • f(-3) = |3| + 2 = 5  so it has the point (-3, 5)
  • f(0) = |-0| + 2 = 2  so it has the point (0, 2)
  • f(3) =  |-3| + 2 = 5  so it has the point (3, 5).

And all the other options can be trivially discarded (by evaluating them).

So the two correct options are:

  • f(x) = |x| + 2
  • f(x) = |-x| + 2

If you want to learn more about absolute value functions:

brainly.com/question/3381225

#SPJ1

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Ratling [72]

All these cases represent experiments whose outcomes are all equaly likely. What we mean is that the cards have all the same probability of being dealt (1/52), and all the spaces of the spinner have the same probability of being landed into (1/5).

These probabilities are computed as 1 over all the possible outcomes.

(a) If you want a heart card and a five, you want the 5 of hearts. So, only one card would satisfy your request, and thus you have probability 1/52 of dealing the 5 of hearts.

\dfrac{1}{52}\approx 0.019 = 1.9\%

(b) There are four 10s and four Jacks in the deck, so 8 cards satisfy your request. With probability 8/52, you'll be dealt a Jack or a 10.

\dfrac{8}{52}=\dfrac{2}{13}\approx 0.154 = 15.4\%

(c) You have two "good" outcomes out of 5, so your probability is 2/5.

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