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3 years ago

The absolute value of this number is less than 1/2 but greater than 1/10

Mathematics

1 answer:

Anastasy [175]3 years ago

6 0

Ok, so I assume this is an equation because there could be multiple exact answers

1/10 < |x| < 1/2

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What is the decimal form of -4 7/8

svetlana [45]

$-4\frac{7}{8}=-4\frac{7\cdot125}{8\cdot125}=-4\frac{875}{1000}=\boxed{-4.875}$

4 0

3 years ago

The basketball team spends 20 minutes running laps and at least 15 minutes discussing plays. Practice lasts one hour and 45 minu

Allushta [10]

Answer:

x ≤ 75

Step-by-step explanation:

The computation of the inequality function is as follows:

Let us assume the remaining time left for other drills be x

Given that the team spends 20 minutes for running laps

And minimum of 15 minutes for discussing plays

Also practicing for last one hour and 45 minutes

Now as we know that

1 hour = 60 minutes

So total minutes would be

= 60 + 45

= 105 minutes

Total minutes spend by the team is

= 20 + 15

= 35 minutes

So now the remaining time left is

x ≤ 105 - 35

x ≤ 75

8 0

3 years ago

A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa

BlackZzzverrR [31]

<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

$1/2\times1/2\times1/2\times1/2=1/16$

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have $2^{4}$ or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = $\frac{4!}{2!2!}$ = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = $1/2\times1/2\times1/2\times1/2=1/16$

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = $1/16+1/16+1/16+1/16+1/16=5/16$

6 0

3 years ago

The edge of a cube is 4 inches. The area of a cross section perpendicular to one face is ___square inches, and its perimeter is_

diamong [38]

Try 8 and 12.......................................

3 0

3 years ago

Read 2 more answers

Please help with this

KonstantinChe [14]

I believe the answer is 32

4 0

3 years ago