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amm1812
3 years ago
12

Hosting a dinner party for 38 people, you plan to serve peach pie for dessert. Each pie has 8 slices. How many pies must you buy

to ensure each guest gets 1 slice?
Mathematics
2 answers:
irga5000 [103]3 years ago
6 0
<span>38/8=4-6/8
You need at least 5 pies for the dinner party. You can eat the two leftover slices after the guests have left



</span>
maw [93]3 years ago
5 0
8 peices times 5 =40
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navik [9.2K]

Answer:

Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Step-by-step explanation:

<u>Step 1:  Multiply</u>

<u />(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\

(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}

(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x}  )

2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}

10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Answer:  Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

6 0
3 years ago
Read 2 more answers
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Andre45 [30]
Use similar volume to calculate
which is the (ratio of edges)^3 = (ration of volume)
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(3/4)^3 = y/320
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7 0
3 years ago
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julsineya [31]
72+72+102=<span>246 is your Answer</span>
6 0
3 years ago
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K=mv^2/2 solve for v
matrenka [14]

Answer: v=\sqrt[]{\frac{2K}{m} }

Step-by-step explanation:

K=\frac{mv^2}{2}

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

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Divide by m to isolate v^2.

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To eliminate the square and isolate v, extract the square root.

\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}

\sqrt[]{\frac{2K}{m} }=v

let's rewrite it in a way that v is in the left side.

v=\sqrt[]{\frac{2K}{m} }

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vivado [14]

Answer:

Circumference : 18.84 inches

Radius: 3 inches

6 0
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