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Finger [1]
3 years ago
10

PLEASE ANSWER ASAP

Mathematics
1 answer:
STatiana [176]3 years ago
5 0

Answer:

2/9 is the correct option.

Step-by-step explanation:

As the spinner is numbered 2, 4 and 5

The general formula for probability :

P(A) = n(A) / n(S)

n(S) is the number of whole states occur in two spins which is 3 × 3 = 9

n(A) is the event that Rico will get a product of 20.

n(A) = 2   ∵ 4 × 5 and 5 × 4 will bring the product 20.

Therefor, the probability that Rico will get a product of 20 when Rico spins the spinner twice will be:

P(A) = n(A) / n(S)

       = 2/9

Therefore, 2/9 is the correct option.

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Meenu bought two fans for ₹1200 each. She sold one at a loss of 5% and the other at a profit of 10%. Find the selling price of e
Vinvika [58]
<h3><u>Solution: </u></h3>

Overall<u> </u>CP of each fan = ₹1200 .

One is sold at a loss of 5% .

  • ( This means if CP is ₹100, SP is ₹95 ) .

• Therefore,When CP is ₹1200 , Then SP is ₹ 1140.

=  >  \frac{95}{100}  \times 1200 = 1140

Also,Second fan is sold at a profit of 10% .

  • It means , If CP is ₹100 , SP is ₹110.

Therefore , When CP is ₹1200 , Then SP is ₹1320.

<u>• We need to find the combined CP and SP to say whether there was an overall profit or Loss.</u><u>.</u>

  • Total CP = ₹ 1200 + ₹ 1200 = ₹ 2400.
  • Total SP = ₹ 1140 + ₹ 1320 = ₹ 2460.

Since total SP > total CP , A profit of ₹ ( 2460 - 2400 ) or ₹60 has been made ..

<h3>Hope this helps you :)</h3>
4 0
3 years ago
jessica has 56 arcade tickets to give away she gives them all to her 8 friends who share them equally how many tickets does each
zhenek [66]
Each of the friends get 7 tickets
8 0
3 years ago
Match the transformation of the polynomial function f(x) = 2x3 − x2 − 5x + 3 with the resulting function.
AlekseyPX

Answer:

Parent Function: g(x)=x3

Horizontal Shift: Right 0.167 Units

Vertical Shift: Up 2.149Units

Reflection about the x-axis: None

Reflection about the y-axis: Reflected

Vertical Compression or Stretch: Stretched

Step-by-step explanation:

To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.

3 0
4 years ago
Harold uses the binomial theorem to expand the binomial (3x^5 - 1/9y^3)^4
riadik2000 [5.3K]
<h3><em>The complete question:</em></h3>

<u><em> </em></u><u>Harold uses the binomial theorem to expand the binomial </u>(3x^5 -\dfrac{1}{9}y^3)^4<u />

<u>(a)    What is the sum in summation notation that he uses to express the expansion? </u>

<u>(b)    Write the simplified terms of the expansion.</u>

Answer:

(a). (3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n}  \binom{4}{k}(3x^5)^{4-k}( -\dfrac{1}{9}y^3)^k $$

(b).(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561}

Step-by-step explanation:

(a).

The binomial theorem says

(x+y)^n=$$\sum_{k=0}^{n}  \binom{n}{k}x^{n-k}y^k $$

For our binomial this gives

\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=$$\sum_{k=0}^{n}  \binom{4}{k}x^{4-k}y^k $$}

(b).

We simplify the terms of the expansion and get:

$$\sum_{k=0}^{n}  \binom{4}{k}(3x^5)^{4-k}y^k $$= \binom{4}{0}(3x^5)^{4-0}(-\dfrac{1}{9}y^3 )^0+\binom{4}{1}(3x^5)^{4-1}(-\dfrac{1}{9}y^3 )^1+\\\\\binom{4}{2}(3x^5)^{4-2}(-\dfrac{1}{9}y^3 )^2+\binom{4}{3}(3x^5)^{4-3}(-\dfrac{1}{9}y^3 )^3+\binom{4}{4}(3x^5)^{4-4}(-\dfrac{1}{9}y^3 )^4

$$\sum_{k=0}^{n}  \binom{4}{k}(3x^5)^{4-k}(-\frac{1}{9}y^3 )^k $$= (3x^5)^{4}+4(3x^5)^{3}(-\frac{1}{9}y^3 )+6(3x^5)^{2}(-\frac{1}{9}y^3 )^2+\\\\4(3x^5)(-\frac{1}{9}y^3 )^3+(-\frac{1}{9}y^3 )^4

\boxed{(3x^5 -\dfrac{1}{9}y^3)^4=81x^{20}-12x^{15}y^3+\dfrac{2x^{10}y^6}{3}-\dfrac{4x^5y^9}{243}+\frac{y^{12}}{6561}   }

3 0
3 years ago
In a garden, 1/3 of the flower are yellow,1/6 of them are pink, and 1/3 of the remaining flowers are red.If there are 120 flower
balu736 [363]

Answer:

20 Red flowers

40 Yellow flowers

20 Pink flowers

Step-by-step explanation:

1/3 of 120 is 40

1/6 of 120 is 20

40+20=60

120-60=60

Remaining=60

1/3 of 60 is 20

3 0
3 years ago
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