What you do is "x" times 75/100 equals 60. Thus you get 80
Answer:
Additive inverse : j(x) = -x + 24
Multiplicative inverse : k(x) = 1/x-24
Step-by-step explanation:
I literally have no idea how, I got this answer off of quizlet :) have a good day.
ANSWER
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EXPLANATION
First equation:
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Second equation:
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Let us equate the two equations and solve for x.
This implies that;

Group similar terms to obtain:
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Simplify:
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Divide both sides by 3

Put x=-2 into any of the equations.
I will put x=-2 into the first equation:

This implies that,

Answer:
see explanation
Step-by-step explanation:
(a)
Given
2k - 6k² + 4k³ ← factor out 2k from each term
= 2k(1 - 3k + 2k²)
To factor the quadratic
Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)
The factors are - 1 and - 2
Use these factors to split the k- term
1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )
1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term
= (1 - k)(1 - 2k)
1 - 3k + 2k² = (1 - k)(1 - 2k) and
2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)
(b)
Given
2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )
= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term
= (x - 2y)(2a + 3b)