Question

Starting from 105 feet away a person on a bicycle rides toward a checkpoint and then passes it.the rider is traveling at a constant rate of 35 feet per second.The distance between the bicycle and the checkpoint given by the equation is D=|105-35t|.at what times is the bike 60 feet away from the checkpoint?
A.1.3 sec and 2.6 sec
B.1.3 sec and 4.7 sec
c.1.1 sec and 2.6 sec
d.4.7 sec and 9.4 sec
WHO EVER ANSWERS IT FIRST AND RIGHT GETS BRAINIEST

Answer 1

Answer:

The correct option is B.

Step-by-step explanation:

It is given that starting from 105 feet away a person on a bicycle rides toward a checkpoint and then passes it.the rider is traveling at a constant rate of 35 feet per second.

The distance between the bicycle and the checkpoint given by the equation

$D=|105-35t|$

We have to find the times  at which the bike 60 feet away from the checkpoint.

Substitute D=60 i the given equation.

$60=|105-35t|$

$\pm 60=105-35t$

Case 1:

$60=105-35t$

Subtract 105 from both the sides.

$60-105=-35t$

$-45=-35t$

Divide both sides by -35.

$1.2857=t$

$t\approx 1.3$

Case 2:

$-60=105-35t$

Subtract 105 from both the sides.

$-60-105=-35t$

$-165=-35t$

Divide both sides by -35.

$4.71428=t$

$t\approx 4.7$

The bike is 60 feet away from the checkpoint at 1.3 sec and 4.7 sec. Therefore the correct option is B.fore the correct option is B.

Answer 2

The answer is B. 1.3 sec and 4.7 sec