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fenix001 [56]
3 years ago
10

A 118.63 g sample of SrCl2·6H2O was heated and 34.81 grams of water were recovered from the sample. What percent of the original

H2O remains in the sample following this heating?
Chemistry
1 answer:
Oliga [24]3 years ago
8 0
Percentage mass of water in SrCl₂<span>·6H</span>₂O
= (6 x 18) / (88 + 35.5 x 2 + 6 x 18)
= 40.4%

Mass of water in sample originally₂:
118.63 x 40.4%
= 47.9 grams

Percentage remaining = (47.9 - 34.81) / 47.9 x 100
= 27.3%
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