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uranmaximum [27]
2 years ago
9

Reaction between iodine solution and polysaccharides

Chemistry
2 answers:
Radda [10]2 years ago
8 0

Explanation:

7 4th CNN to CNN u 4th f7 4th d7 hmm

ElenaW [278]2 years ago
3 0

In the iodine test in this lodine and potassium iodide (KI) in water, the solution turns light orange brown colour.

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If the atomic weight of nitrogen is 14.01, what is the mass of the nitrogen atoms in one mole of cadmium nitrate, Cd(NOÀ)
Nadya [2.5K]
The answer is 28.02.

The chemical formula for cadmium nitrate is Cd(NO₃)₂.

There are in total 2 nitrogen atoms in Cd(NO₃)₂. If <span>the atomic weight of nitrogen is 14.01</span>, the mass <span>of two nitrogen atoms in one mole of cadmium nitrate is 28.02:
2 </span>· 14.01 = 28.02
8 0
3 years ago
MethaneProteinAlcohol can be found in beer, wine and liquor.
artcher [175]
The correct answer is alcohol. It is the common component in beer, wine and any liquor. Usually, alcohol is produced by fermentation of organic products containing glucose to produce alcohol, specifically ethanol, as the important product and the by-products water and carbon dioxide. 
3 0
3 years ago
When Z-4,5-dimethyloct-4-ene is treated with hydrogen chloride, HCl, the result is:________.
Vika [28.1K]

Answer:

The  correct option is  c

Explanation:

The chemical equation for the reaction of  Z-4,5-dimethyloct-4-ene and HCl is shown on the first uploaded image

Now looking at the product we see that there are two who has four different groups attached to them this carbon are known as chiral carbons hence the product formed is a pair of diastereomers

6 0
3 years ago
Sodium aton has lower electron affinity than chlorine atom why
Citrus2011 [14]
Electron affinity is the energy released when an electron is accepted by a neutral atom forming a negative ion. Chlorine has the higher electron affinity because it readily accepts an electron to become more stable. On the other hand, sodium have to give up an electron to complete its valence shell.
5 0
3 years ago
Suppose 180 ml of 3.52x10^-4 M NaOH is mixed with 220 mL of 2.47x10^-4 M MgCl2.
velikii [3]
When in water, MgCl2 dissociates into magnesium ions and Cl- ions and NaOH into Na and OH ions. The equation is as follows:

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The initial concentrations are as follows:

[Mg2+] = .220(<span> 2.47x10^-4) / .220+.180 = 1.36x10^-4 M Mg2+
</span>[OH-] = .180 (3.52x10^-4) / .220+.180 = 1.58x10^-4 M OH-
6 0
3 years ago
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