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3 years ago

The following properties are either physical or chemical. Which one is different from the rest based on those two categories?

Chemistry

2 answers:

larisa86 [58]3 years ago

6 0

Answer:

Thermal conductivity

Explanation:

pychu [463]3 years ago

3 0

Answer:

Thermal conductivity

Explanation:

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What mass of water is produced by the combustion 1.2 x 10 exp 26 molecules of butane

algol [13]

Answer:

17.94 kg of water

Explanation:

The combustion reaction of balanced butane (C₄H₁₀) is as follows:

2 C₄H₁₀ + 13 O₂ ⇒ 8 CO₂ + 10 H₂O

The amount of butane molecules can be transferred to moles to establish the stoichiometric relationship with water and calculate the moles of water that are formed:

6.02x10²³ molecules _____ 1 mol of butane

1.2x10²⁶ molecules _____ X = 199.34 moles of butane

Calculation: 1.2x10²⁶ molecules x 1 mol / 6.02x10²³ molecules = 199.34 moles of butane

According to the balanced equation:

2 moles butane _____ 10 moles of water

199.34 moles of butane _____ X = 996.68 moles of water

Calculation: 199.34 moles x 10 moles / 2 moles = 996.68 moles of water

And now, you can calculate the mass of the amount of moles obtained from water:

1 mole of water _____ 18 g

996.68 moles of water _____ X = 17.94 kg of water

Calculation: 996.68 moles x 18g / 1 mole = 17940.20g ≡ 17.94 kg of water

Therefore, the combustion of 1.2x10²⁶ butane molecules produces 17.94 kg of water.

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Write the three factors that affect surface ocean currents

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global wind patterns, rotation of the earth, shape of ocean basins.

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Which of the following ions/atoms has the smallest radius?

Anna11 [10]

Answer:

B I believe im sorry if it's not right

8 0

3 years ago

Imagine a box floating in space. The following picture shows all the forces acting on this box.

svetoff [14.1K]

50 Newton’s upwards.

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DUE TODAY EXTREMELY IMPORTANT PLEASE PLEASE PLEASE HELP ME ASAPPPPPPPP CHEMISTRY!!!!!!!!!!!!!!!!!!! I WOULD APPRECIATE IT ALOT T

musickatia [10]

Answer:

Here's what I get

Explanation:

3. Molar concentration by formula.

$\begin{array}{rcl}M_{\text{a}}V_{a} & = & M_{\text{b}}V_{b}\\M_{a} \times \text{0.025 00 L} & = & \text{0.3840 mol/L} \times \text{0.034 52 L}\\0.025 00M_{a}\text{ L} & = & \text{0.013 26 mol}\\M_{a}&= &\dfrac{\text{0.013 26 mol}}{\text{0.025 00 L}}\\\\& = &\textbf{0.5302 mol/L}\end{array}$

(i) Comparison of molar concentrations

The formula gives a calculated value of 0.5302 mol·L⁻¹.

Dimensional analysis gives a calculated value of 0.1767 mol·L⁻¹.

The first value is three times the second.

It is wrong because the formula assumes that the acid supplies just enough moles of H⁺ to neutralize the OH⁻ from the NaOH.

Instead, I mol of H₃PO₄ provides 3 mol of H⁺, so your calculated concentration is three times the true value.

(ii) When is the formula acceptable?

The formula is acceptable only when the molar ratio of acid to base is 1:1.

Examples are

HCl + NaOH ⟶ NaCl + H₂O

H₂SO₄ + Ca(OH)₂ ⟶ CaSO₄ + 2H₂O

H₃PO₄ + Al(OH)₃ ⟶ AlPO₄ + 3H₂O

8 0

3 years ago