The first four terms of the series probably refer to the first four partial sums.




which you can compute either by adding one term at a time, or using the well-known formula,

(I can provide a link to a derivation I gave in a nearly identical question in the comments)
The series converges as

if and only if

, which is certainly the case here, since

.
Extrapolating from the formula above, the sum of the convergent series is

so the sum for this series is

.
6+3+5+7= 21 balls total
Choose 2 balls
21C2= 210 total number of ways you could have chosen the two balls
(nCr- n=total, r=choose)
Total green balls= 3
You choose first green ball out of 3
3C1
Then you choose second green ball out of the 2 green balls left
2C1
Multiply these two outcomes
3C1•2C1= 6
Probability=
6/210= 1/35
Answer:
a.<55, -27>
Step-by-step explanation:
The given vectors are u = <7, -3>, v = <-9, 5>.
We want to find 4u - 3v.
We substitute the vectors and multiply by the scalars.
4u - 3v=4<7, -3>-3 <-9, 5>.
4u - 3v=<28, -12>- <-27, 15>.
4u - 3v=<28--27, -12-15>
4u - 3v=<55, -27>
Answer:
1/x^4
Step-by-step explanation:
Answer:
x=2
Solve for x by simplifying both sides of the equation, then isolating the variable.