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3 years ago

Help me solve this..! Please!

Mathematics

1 answer:

stiv31 [10]3 years ago

3 0

Answer:

x=2

Solve for x by simplifying both sides of the equation, then isolating the variable.

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Find the product of 2x^4(4x^2 + 3x + 1).

lianna [129]

We want to find the product:

$\displaystyle{ 2x^4\cdot(4x^2 + 3x + 1)$ .

By the $\text{Distributive property}$ , we distribute $2x^4$ over each of the three terms inside the parenthesis:

$\displaystyle{ 2x^4\cdot(4x^2 + 3x + 1)=2x^4\cdot4x^2+2x^4\cdot3x+2x^4\cdot1$ .

Multiplying the coefficients, and adding the exponents we get:

$8x^6+6x^5+2x^4$ .

Answer: $8x^6+6x^5+2x^4$ .

5 0

3 years ago

PLEASE HELP DUE TOMORROW 1. An artist is selling children’s crafts. Necklaces cost 2.25 each and bracelets cost 1.50 per each. a

Tems11 [23]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

Cost per bracelet = 1.50

Cost per necklace = 2.25

Let :

number of necklace = n

Number of bracelet = b

Cost equation C ;

C = 1.5b + 2.25n

Number of necklace that could be sold for exactly $12

5 necklaces and 1 bracelet :

1.5 + 2.25(5) = 12.75

•2 necklaces and 5 bracelets:

1.5(5) + 2.25(2) = 12

• 3 necklaces and 3 bracelets

1.5(3) + 2.25(3) = 11.25

• 4 necklaces and 2 bracelets

1.5(2) + 2.25(4) = 12

• 3 necklaces and 5 bracelets

1.5(5) + 2.25(3) = 14.25

• 6 necklaces and no bracelets •

1.5(0) + 2.25(6) = 13.5

No necklaces and 8 bracelets

1.5(8) + 2.25(0) = 12

Amount charged per Tshirt = c

Setup fee = $40

Number of students in drama club = 21

Total cost of order = $187

Calculate C ;

Total order cost = set up fee + (cost per shirt * number of shirts)

Total order cost = 40 + 21c

187 = 40 + 21c

187 - 40 = 21c

147 = 21c

c = 147 / 21

C = 7

Hence cost per shirt = $7

5 0

3 years ago

Which statements are true about ΔJKL and ΔLMN? Select all that apply.

svp [43]

Answer:

A. ΔJKL and ΔLMN have only one pair of angles that are congruent

C. ΔJKL has angles that measure $50^o,60^o,70^o$

Step-by-step explanation:

step 1

Find the value of x

we know that

$m\angle KLJ=m\angle MLN$ ----> by vertical angles

substitute the given values

$(6x-2)^o=(5x+10)^o$

solve for x

$6x-5x=10+2\\x=12$

step 2

Find the measure of the interior angles of triangle JKL

we have

$m\angle KLJ=(6(12)-2)=70^o$

$m\angle KJL=(5(12))=60^o$

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle JKL=180^o-130^o=50^o$

therefore

Triangle JKL has angles that measure $50^o,60^o,70^o$

step 3

Find the measure of the interior angles of triangle LMN

we have

$m\angle MLN=(5(12)+10)=70^o$

$m\angle LMN=(6(12)-7)=65^o$

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle LNM=180^o-135^o=45^o$

Triangle LMN has angles that measure $45^o,65^o,70^o$

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

The corresponding angles of triangle JKL and LMN are not congruent

therefore

The triangles are not similar

<u><em>Verify each statement</em></u>

Part a) ΔJKL and ΔLMN have only one pair of angles that are congruent

The statement is true (see the explanation)

Part b) ΔJKL and ΔLMN have two pairs of angles that are congruent

The statement is false

Because have only one pair of angles that are congruent

Part c) ΔJKL has angles that measure $50^o,60^o,70^o$

The statement is true (see the explanation)

Part d) ΔLMN has angles that measure $50^o,60^o,70^o$

The statement is false

Because, Triangle LMN has angles that measure $45^o,65^o,70^o$

Part e) ΔJKL and ΔLMN are similar

The statement is false

Because, the corresponding angles are not congruent

6 0

3 years ago

Help me with this question

Vlad [161]

Man why you asking us like we know

8 0

3 years ago

In circle P, what is the measure of ADB?

Arada [10]

Answer:

arc ADB = 270°

Step-by-step explanation:

Arc ADB is the remainder of the circle after subtracting 90° arc AB. Its measure is ...

ADB = 360° -90° = 270°

3 0

3 years ago