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2 years ago

Simplify the expression. x^5/x^9

Mathematics

1 answer:

ryzh [129]2 years ago

8 0

Answer:

1/x^4

Step-by-step explanation:

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What is the equation of a line perpendicular to -x +2=y that intersects the line at (-1.5, 3.5)?

Nina [5.8K]

Answer:

y=x+5

Step-by-step explanation:

y-y1=m(x-x1)

y=-x+2

slope of y=-x+2 is -1, perpendicular slope is 1

y-3.5=1(x-(-1.5))

y-3.5=x+1.5

y=x+5

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2 years ago

How is the Expanded Notation Method used for 82 times 3

MaRussiya [10]

80X3 PLUS 2x3 that is awnser

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3 years ago

Read 2 more answers

I need to an explanation about this formula.

sergeinik [125]

I would answer but i can not see what it says.... Sorry

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3 years ago

Opal West has made a claim for an injury of a visiting ten-year-old who broke a toe in the family swimming

lozanna [386]

Answer:

C. $1,103.88

Step-by-step explanation:

The total cost is:

1785.42 × 1.06635 = 1903.88

There was no physical damage to the pool, only an accidental injury. So Opal pays the $800 deductible, and the insurance pays the rest, which is:

1903.88 − 800 = 1103.88

5 0

2 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

2 years ago