Tuesday jane walked 52/3km at recess.they walked the same for 3 days.how much di d she walk.

Mathematics

2 answers:

Afina-wow [57]3 years ago

6 0

Answer: 52 km

Step-by-step explanation:

since she walked the same distance for 3 days:

52/3 * 3 = 52

Bumek [7]3 years ago

4 0

Answer: 17km

Step-by-step explanation:

You have to multiple 5 and 2/3 by 3, which gives you 15 and 6/3. Convert the improper fraction 6/3 to 2.

15 + 2 = 17.

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If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

8 0

3 years ago

How do you substitute 4(x) into the inequality 1/2x+5y-10<0 to find the possible value of y?

Veseljchak [2.6K]

You put 4 in the X
1/2(4)+5y-10<0
2+5y-10<0
-8+5y<0
5Y<8
Y<8/5

3 0

2 years ago

Sorry i know it is too blurry but can u at least try

raketka [301]

Answer:

Step-by-step explanation:

Draw your figures the same way as I did, and see if you understand the explanations before writing them down. It's most important to learn from your work :)