as you already know, to get the inverse of any expression we start off by doing a quick switcheroo on the variables and then solving for "y", let's do so.
![\stackrel{h(x)}{y}~~ = ~~6\sqrt[3]{2x+5}-1\implies \stackrel{\textit{quick switcheroo}}{x~~ = ~~6\sqrt[3]{2y+5}-1} \\\\\\ x+1=6\sqrt[3]{2y+5}\implies \cfrac{x+1}{6}=\sqrt[3]{2y+5}\implies \left( \cfrac{x+1}{6} \right)^3=\left( \sqrt[3]{2y+5} \right)^3](https://tex.z-dn.net/?f=%5Cstackrel%7Bh%28x%29%7D%7By%7D~~%20%3D%20~~6%5Csqrt%5B3%5D%7B2x%2B5%7D-1%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bquick%20switcheroo%7D%7D%7Bx~~%20%3D%20~~6%5Csqrt%5B3%5D%7B2y%2B5%7D-1%7D%20%5C%5C%5C%5C%5C%5C%20x%2B1%3D6%5Csqrt%5B3%5D%7B2y%2B5%7D%5Cimplies%20%5Ccfrac%7Bx%2B1%7D%7B6%7D%3D%5Csqrt%5B3%5D%7B2y%2B5%7D%5Cimplies%20%5Cleft%28%20%5Ccfrac%7Bx%2B1%7D%7B6%7D%20%5Cright%29%5E3%3D%5Cleft%28%20%5Csqrt%5B3%5D%7B2y%2B5%7D%20%5Cright%29%5E3)
The scale factor is some number between 0 and 1 (not including either endpoint) because the image is smaller than the preimage.
Triangle ABC is the preimage, or the "before"; while triangle A'B'C' is the image, which is the "after".
preimage ----> image
before ----> after
Omggg hiii you divide both sides by 14 and your answer would be 6
I need to see the picture I don’t know which polynomials
Answer:
Medium
Step-by-step explanation:
Cause that what it is.
