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3 years ago

How do you do this question?

Mathematics

1 answer:

Alla [95]3 years ago

8 0

Step-by-step explanation:

∫ erf(x) dx

Integrate by parts.

If u = erf(x), then du = 2/√π e^(-x²) dx.

If dv = dx, then v = x.

∫ u dv = uv − ∫ v du

= x erf(x) − ∫ 2/√π x e^(-x²) dx

= x erf(x) + 1/√π ∫ -2x e^(-x²) dx

Substitution.

If u = -x², then du = -2x dx.

= x erf(x) + 1/√π ∫ e^u du

= x erf(x) + 1/√π e^u + C

= x erf(x) + 1/√π e^(-x²) + C

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CASE3: Odd degree and positive leading coefficient

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CASE4: Odd degree and negative leading coefficient

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Here in the given case we have odd degree and negative leading coefficient

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3 years ago

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solniwko [45]

Answer:

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54.73

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2 years ago

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Step-by-step explanation:

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