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3 years ago

How do you do this question?

Mathematics

1 answer:

Alla [95]3 years ago

8 0

Step-by-step explanation:

∫ erf(x) dx

Integrate by parts.

If u = erf(x), then du = 2/√π e^(-x²) dx.

If dv = dx, then v = x.

∫ u dv = uv − ∫ v du

= x erf(x) − ∫ 2/√π x e^(-x²) dx

= x erf(x) + 1/√π ∫ -2x e^(-x²) dx

Substitution.

If u = -x², then du = -2x dx.

= x erf(x) + 1/√π ∫ e^u du

= x erf(x) + 1/√π e^u + C

= x erf(x) + 1/√π e^(-x²) + C

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I need help with these please

notsponge [240]

Answer:

1a - no

1b - yes

1c - no

2 - 1.5 grams of protein

3 - a solution to this equation tells us how many grams of protein/fat there could be depending on how many grams of the other there are. a solution to this is 6 grams of protein and 4 grams of fat.

Step-by-step explanation:

4(5)+9(2)=60

20+18=60

38=60

the equation is false

4(10.5)+9(2)=60

42+18=60

60=60

the equation is true

4(8)+9(4)=60

32+36=60

68=60

the equation is not true

plug in 6 for the f value

4p+9(6)=60

4p+54=60

subtract 54 from both sides

4p=6

divide both sides by 4 to get p alone

p=1.5

a possible solution can be seen by graphing the equation using the intercepts. the intercepts for this equation are (15,0) and (0,6.6). attached is an image of the graph. the points where the line crosses are possible solutions. the line crosses the point (6,4) on the graph, which represents 6 grams of protein and 4 grams of fat. you can also check this by plugging these values into the equation.

4 0

2 years ago

12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely

AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is $6 a b^{2}(a+2)(2 a-1)$

<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

$12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

Taking $b^2$ as common term,

$b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)$

Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

4 0

2 years ago

0=4t-16t^2 Solve this please

vaieri [72.5K]

Answer:

$\large\boxed{t=0\ \vee\ t=\dfrac{1}{4}}$

Step-by-step explanation:

$4t-16t^2=0\qquad\text{divide both sides by 4}\\\\\dfrac{4t}{4}-\dfrac{16t^2}{4}=\dfrac{0}{4}\\\\t-4t^2=0\\\\t(1-4t)=0\iff t=0\ \vee\ 1-4t=0\\\\1-4t=0\qquad\text{subtract 1 from both sides}\\\\-4t=-1\qquad\text{divide both sides by (-4)}\\\\t=\dfrac{1}{4}$

7 0

2 years ago

Find the value of 5.8 ÷ 1.2. Round your answer to the nearest hundredth. A. 5.24 B. 4.83 C. 6.96 D. 4.6

Sedaia [141]

5.8/1.2 = 58/12 = 4.83333333

rounded to the nearest hundredth

4.83

8 0

3 years ago

Read 2 more answers

1. If you are asked to use elimination to solve for x", what do you need to multiply the bottom equation by to eliminate "y?

hram777 [196]

Answer:

-5

Step-by-step explanation:

There is different ways to solve methods of elimination but if you wanted to cancel y out you would multiply by the opposite sign....for example

7x + 5y = 19

-5 (2x + y = 19) ---> -10x -5y = 95

this would cancel out your y to solve for x so you can plug it back in and solve! hope this helps!!!

6 0

2 years ago