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Oliga [24]
3 years ago
9

When you move a circle vertically, the number that is part of the yterm changes.

Mathematics
2 answers:
GREYUIT [131]3 years ago
4 0

Answer:

true

Step-by-step explanation:

svetlana [45]3 years ago
3 0

Answer:

Step-by-step explanation:

The general equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2.  You seem to be referring to "the y-coordinate of the center of the circle," that is, h in (h, k).

Yes, if you move a circle vertically, the y-coordinate of the center changes.

It's unclear what you're asking for help with.  Please try to be more specific next time.

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seraphim [82]

Answer:

Step-by-step explanation:

52.1 x 2.29 = 119.309

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What is the value of x
Hoochie [10]

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable

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(URGENT) need this answer today​
Vlad [161]

Answer: 19.5

Step-by-step explanation:

Use Pythagorean theorem to find the diagonal as it is a right triangle.

6 0
3 years ago
The digits 1,2,3,4,5,6,7 and 8 are arranged randomly to form a three-digit number find the probability that the number is even a
Korvikt [17]
So each digits can only be selected once.

Let's start counting desired outcome.

Hundred position need to be at least 8. There is only one possible digits. So we will go with 8 and then there are 7 remaining digits.

One position can only be 2,4,6. because we need number to be even. So that's 3 possible digits. We will take one. 6 digits remaining.

Ten position can be anything so that would be 6 possible digits.

So the number of desired outcomes is 3·6 = 18.

Now count all outcomes.

Hundred, ten, and one position can get any digits

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4 0
3 years ago
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Stuck on these two shapes <br>need help in working out the surface area​
ArbitrLikvidat [17]

Answer:

Part 1) The surface area of the triangular prism is SA=660\ cm^{2}

Part 2) The surface area of the trapezoidal prism is SA=2,864\ cm^{2}

Step-by-step explanation:

Part 1) Find the surface area of the triangular prism

we know that

The surface area is equal to

SA=2B+PL

where

B is the area of the triangular base of the prism

P is the perimeter of the base of the prism

L is the length of the prism

<u>Find the area of the triangular base B</u>

B=\frac{1}{2}(10)(12)=60\ cm^{2}

<u>Find the perimeter of the base P</u>

P=10+13+13=36\ cm

L=15\ cm

substitute the values

SA=2(60)+(36)(15)=660\ cm^{2}

Part 2) Find the surface area of the trapezoidal  prism

we know that

The surface area is equal to

SA=2B+PL

where

B is the area of the trapezoid base of the prism

P is the perimeter of the base of the prism

L is the length of the prism

<u>Find the area of the trapezoid base B</u>

B=\frac{1}{2}(28+15)(8)=172\ cm^{2}

<u>Find the perimeter of the base P</u>

P=15+28+10+10=63\ cm

L=40\ cm

substitute the values

SA=2(172)+(63)(40)=2,864\ cm^{2}

4 0
3 years ago
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