Question

Stuck on these two shapes need help in working out the surface area​

Answer 1

Answer:

Part 1) The surface area of the triangular prism is $SA=660\ cm^{2}$

Part 2) The surface area of the trapezoidal prism is $SA=2,864\ cm^{2}$

Step-by-step explanation:

Part 1) Find the surface area of the triangular prism

we know that

The surface area is equal to

$SA=2B+PL$

where

B is the area of the triangular base of the prism

P is the perimeter of the base of the prism

L is the length of the prism

Find the area of the triangular base B

$B=\frac{1}{2}(10)(12)=60\ cm^{2}$

Find the perimeter of the base P

$P=10+13+13=36\ cm$

$L=15\ cm$

substitute the values

$SA=2(60)+(36)(15)=660\ cm^{2}$

Part 2) Find the surface area of the trapezoidal  prism

we know that

The surface area is equal to

$SA=2B+PL$

where

B is the area of the trapezoid base of the prism

P is the perimeter of the base of the prism

L is the length of the prism

Find the area of the trapezoid base B

$B=\frac{1}{2}(28+15)(8)=172\ cm^{2}$

Find the perimeter of the base P

$P=15+28+10+10=63\ cm$

$L=40\ cm$

substitute the values

$SA=2(172)+(63)(40)=2,864\ cm^{2}$