Answer:
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Step-by-step explanation:
least of 3 consecutive integers is a, and the greatest is z
if a is the least one
we know that integers differ by value of 1.
example -2, -1, 0, 1,2
they all differ by
then next consecutive integer will be a+1
third integer will be second integer +1 = a+1 + 1 = a+2
Thus, 3 consecutive integer
a , a+1, a+2
but given that greatest is z
thus, a+2 is greatest and hence
a+2 = z
we have to find value of a + 2z/ 2 in terms of a
a + 2z/ 2 = a + 2(a+2)/2 = (a+ 2a +4)/2 = (3a+4)/2.
The value of a + 2z/ 2 in terms of a is (3a+4)/2
<span>4x</span>² <span>+ 13x + 3=
4x</span>² + 12x + x + 3 =
4x(x+3) + (x+3) =
(4x+1)(x+3)
Answer:
A, B, & C
Step-by-step explanation:
A: -5x +12 = -12x - 12
+12x +12x
7x + 12 = -12
-12 -12
7x = -24 [Divide both sides by 7 to get x]
x = -24/7
B: −5x + 12 = 5x + 12
-5x -5x
-10x + 12 = 12
-12 -12
-10x = 0 [Divide both sides by -10 to get x]
x = 0
C: −5x + 12 = 5x − 5
-5x -5x
-10x + 12 = -5
-12 -12
-10x = -17 [Divide both sides by -10 to get x]
x = 17 / 10
D: −5x + 12 = −5x − 12
+5x +5x
12 ≠ -12 [The statement is false, so it isn't the correct answer]
