All categories

3 years ago

Is 0.66 greater thab 0.066

Mathematics

2 answers:

mestny [16]3 years ago

6 0

yes because 0.66 has 6 in the place value and 0.066 has a zero

Margarita [4]3 years ago

4 0

Though 0.066 has more digits, it does not mean that it is greater than 0.66. So, yes. 0.66 is greater than 0.066.

You might be interested in

A walkway forms one diagonal of a square playground. The walkway is 22 m long. How long is a side of the playground?

nadya68 [22]

You can think of a square as two isosceles right angle triangles and use Pythagoras.

x^2 + x^2 = 22^2
x^2 + x^2 = 484
2x^2 = 484
x^2 = 242
x = 11√2

One side of the playground is 11√2 m long.

5 0

4 years ago

Use substitution to solve the system. -5x + 3y = 19 x = 3y - 11

telo118 [61]

Answer:

x = -2

y = 3

Step-by-step explanation:

-5x + 3y = 19

x = 3y - 11

-5x + 3y = 19

-5(3y - 11) + 3y = 19

-15y + 55 + 3y = 19

-15y + 3y + 55 = 19

-12y + 55 = 19

-12y = 19 - 55

-12y = -36

y = -36/-12

y = 3

x = 3y - 11

x = 3(3) - 11

x = 9 - 11

x = -2

5 0

3 years ago

What is the value of y in the given triangle?

Harlamova29_29 [7]

Answer:

55

Step-by-step explanation:

70+y+y=180 angle sum property

70+2y=180

y=110/2

Y=55

6 0

3 years ago

At an interest rate of 8% compounded annually, how long will it take to double the following investments?

Paladinen [302]

Let's see, if the first one has a Principal of $50, when it doubles the accumulated amount will then be $100,

recall your logarithm rules for an exponential,

$\bf \textit{Logarithm of exponentials}\\\\
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-------------------------------\\\\
\qquad \textit{Compound Interest Earned Amount}
\\\\
$

$\bf A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$100\\
P=\textit{original amount deposited}\to &\$50\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annnually, thus once}
\end{array}\to &1\\
t=years
\end{cases}
\\\\\\
100=50\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 100=50(1.08)^t
\\\\\\
\cfrac{100}{50}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)
\\\\\\
$

$\bf log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\
-------------------------------\\\\
$

now, for the second amount, if the Principal is 500, the accumulated amount is 1000 when doubled,

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$1000\\
P=\textit{original amount deposited}\to &\$500\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annnually, thus once}
\end{array}\to &1\\
t=years
\end{cases}
\\\\\\
1000=500\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 1000=500(1.08)^t
\\\\\\
$

$\bf \cfrac{1000}{500}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)
\\\\\\
log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\
-------------------------------$

now, for the last, Principal is 1700, amount is then 3400,

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$3400\\
P=\textit{original amount deposited}\to &\$1700\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annnually, thus once}
\end{array}\to &1\\
t=years
\end{cases}$

$\bf 3400=1700\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 3400=1700(1.08)^t
\\\\\\
\cfrac{3400}{1700}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)
\\\\\\
log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t$

8 0

4 years ago

1. Using the divisibility rules, above, to say whether each number is divisible by 2, 3, 5, 6, 9 or

melomori [17]

Ok I’m just gonna do that I don’t want you have a girlfriend or no I’m just asking for me to go to get your car I want you guys and you want me a lot more people to to do that you don’t have a

5 0

3 years ago