Answer:
£107.72
Step-by-step explanation:
Given
-- Principal
-- Rate
-- Time
-- compounded once in a year
Required
Determine the compound interest
This is calculated using:
![I = P(1 + \frac{r}{n})^{nt} - P](https://tex.z-dn.net/?f=I%20%3D%20P%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D%20-%20P)
![I = 200(1 + \frac{9\%}{1})^{1*5} - 200](https://tex.z-dn.net/?f=I%20%3D%20200%281%20%2B%20%5Cfrac%7B9%5C%25%7D%7B1%7D%29%5E%7B1%2A5%7D%20-%20200)
![I = 200(1 + \frac{0.09}{1})^5 - 200](https://tex.z-dn.net/?f=I%20%3D%20200%281%20%2B%20%5Cfrac%7B0.09%7D%7B1%7D%29%5E5%20-%20200)
![I = 200(1 + 0.09)^5 - 200](https://tex.z-dn.net/?f=I%20%3D%20200%281%20%2B%200.09%29%5E5%20-%20200)
![I = 200(1.09)^5 - 200](https://tex.z-dn.net/?f=I%20%3D%20200%281.09%29%5E5%20-%20200)
![I = 307.72 - 200](https://tex.z-dn.net/?f=I%20%3D%20307.72%20-%20200)
![I = 107.72](https://tex.z-dn.net/?f=I%20%3D%20107.72)
<em>Hence, the total interest earned is £107.72</em>
Answer:
s represents the shorter leg
3s - 9 represents the longer leg
2s + 1 represents the hypotenuse
(2s + 1)2 = s2 + (3s - 9)2 Pythagorean Theorem
4s2 + 4s + 1 = s2 + 9s2 - 54s + 81 square binomial
4s2 + 4s + 1 = 10s2 - 54s + 81 combine like terms
0 = 6s2 - 58s + 80 set to 0
0 =3s2 - 29s + 40 divide both sides by 2
0 = (3s - 5)(s - 8) FOIL
{5/3, 8}
5/3 is not feasible since 3(5/3) - 9 is negative.
-by-step explanation:
Mhm, absolutely. Notice that we do not have a common unit circle value for any division of 8. But we do have a value for is 7pi/4. Now in order to actually get the value of 7pi/8, we use a half angle formula. So what we do is we will write out the formula and plug 7pi/4 into that formula, this will give us the value of 7pi/8. So the formula we need to plug 7pi/4 into is this:
<span>±<span><span><span>1+cos2θ</span>2</span><span>−−−−−−−−−</span>√</span></span><span>SO if you plug in 7pi/4 for theta in that formula, you think you could simplify it to find 7pi/8?</span>
Answer: try mat way
Step-by-step explanation: