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Elis [28]
2 years ago
6

PLEASE HELP QUICK I HAVE 10 MINUTES

Mathematics
1 answer:
Vlad1618 [11]2 years ago
5 0

Answer:

56.58j = c

Step-by-step explanation:

c = cost

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3 years ago
What is the common denominator of 2/9 and 2/3
GREYUIT [131]

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PLEASE HELP ME, ill give points! Im in the 7th grade
sdas [7]

Answer: y=-5 x=5

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4 0
2 years ago
Jacob and issac decided to run to the basketball court after school the basketball court is 5 1/4 Miles from school the boys run
GenaCL600 [577]

Answer: 1\dfrac{5}{9}\text{ minutes}

Step-by-step explanation:

Complete question is provided in the attachment below.

Given: Jacob and Issac decided to run to the basketball court

Distance between basketball court and school = 5\dfrac{1}{4} miles

=\dfrac{21}{4} miles

Speed = 3\dfrac{3}{8} miles per hour

=\dfrac{27}{8} miles per hour

Since, time = (distance) ÷ ( speed)

Now, the time taken by boys to arrive at the basketball court = \dfrac{21}{4}\div\dfrac{27}{8} hours

=\dfrac{21}{4}\times\dfrac{8}{27}\\\\=\dfrac{7\times2}{9}=\dfrac{14}{9}\\\\=1\dfrac{5}{9}\text{ minutes}

Hence, the required length of time = 1\dfrac{5}{9}\text{ minutes}

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3 years ago
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