Identify a quadrilateral that is not a parallelogram

Mathematics

2 answers:

sp2606 [1]3 years ago

7 0

Answer:

a square, rectangle,trapezoid

Step-by-step explanation:

Leona [35]3 years ago

6 0

Answer:

Trapezium

Step-by-step explanation:

This is a quadrilateral that has no equal sides so it is not a parallelogram. This quadrilateral has one pair of opposite sides parallel.

You might be interested in

flvs hope If $x^2+bx+16$ has at least one real root, find all possible values of $b$. Express your answer in interval notation.

Galina-37 [17]

If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
 b^2-4(1)(16) ≥ 0
 b^2-64 ≥ 0
 (b+8)(b-8) ≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where (b+8)(b-8) is positive.

5 0

3 years ago

Emmy goes through a 50-ounce jug of laundry detergent in 40 loads. At the store, she

Usimov [2.4K]

Observing 150 is 3 times 50
So to keep it equivalent
40 times 3 is 120

4 0

3 years ago

Is anybody in debate?

stira [4]

Answer:

yeah why?

Step-by-step explanation:

4 0

3 years ago

Evaluate the expression for the given value of the variable: 2(x²2) for x=3

zysi [14]

The answer would be 36 because you just plug 3 in for x

8 0

3 years ago

Please help!!!! Please help!!!!

Nimfa-mama [501]

Answer:

44 cm²

Step-by-step explanation:

To find the area of a compound figure like this, we can divide the shape into various rectangles and compute the areas of them separately before adding them together.

There are several ways to divide this shape, but for this we will section the shape into a 3×3 square, 4×2 rectangle, and a 3×9 rectangle.

To find the areas of them, multiple the length by the width.

For the 3×3 square at the top right-

$A=3\cdot 3$