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larisa86 [58]
3 years ago
11

Select the ordered pairs that are solutions to the inequality 2x -3y ≥ 12 (select all that apply) A. (1, -3) B. (8, 1) C. (3, 2)

D. (-2, -6) E. (2, 3) F. (1,8) G. (-3, 1)
Mathematics
2 answers:
satela [25.4K]3 years ago
8 0
If A,
2(1) - 3( - 3) \geqslant 12 \\ 2 + 9 \geqslant 12(wrong)
If B,
2(8) - 3(1) \geqslant 12 \\ 16 - 3 \geqslant 12(correct)
If C,
2(3) - 3(2) \geqslant 12 \\ 6 - 6 \geqslant 12(wrong)
If D,
2( - 2) - 3( - 6) \geqslant 12 \\  - 4 + 18 \geqslant 12(correct)
If E,
2(2) - 3(3) \geqslant 12 \\ 4 - 9 \geqslant 12 (wrong)
If F,
2(1) - 3(8) \geqslant 12 \\ 2 - 24 \geqslant 12(wrong)
If G,
2( - 3) - 3(1) \geqslant 12 \\  - 6 - 3 \geqslant 12(wrong)

The answers are B and D

Hope this helps. - M
AveGali [126]3 years ago
5 0

Answer:

The answers are (8,1) and (-2,-6)

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The average score that Kat gets on her exams is proportional to the amount of time she studies for the exam. Kat scored a 75 aft
siniylev [52]
75/15=90/x
75x=90*15
75x=1350
x=1350/75
x=18
she needed to study 18 hrs to get a 90
4 0
4 years ago
your teacher is giving you a test worth 100 points that contains 40 questions. there are 2point questions on the test. how many
kykrilka [37]
100 = 2t + 4f 
40= t + f
-----------
get t or f by itself first.

f = 40 - t : Then substitute it back into for f in the other equation
100 = 2t + 4f 
100= 2t +4(40-t) 
100= 2t + 160 - 4t
100 = -2t + 160
-160           -160

<u>-60 </u>= <u>-2t
</u>-2        -2

t = 30 (Then plug this into either equation to solve for f)

Therefore,
t = 30 questions
f = 10 questions
3 0
4 years ago
What is the y-value of the vertex of the function f(x) = –(x + 8)(x – 14)? The y-value of the vertex is .
enot [183]
      Best Answer:  <span> y=18x^2+9x+14

y=18(x^2+(1/2)x + 1/16) + 14 - 9/8

y = 18(x + 1/4)^2 + 103/8


For y = a*(x - h)^2 + k, (h, k) the vertex

Your vertex: (- 1/4, 103/8)

Equation of axis of symmetry is x = (x-coordinate of vertex) OR x = - 1/4

y-intercept is y-value when x = 0, y = 14

x-intercept(s) do not exist for this upward opening parabola whose vertex y-value is above the x-axis.

The minimum of the function is the y-value of the vertex, 103/8.
=======================================...

Seems like Dizzle was in too much of a hurry and Jeff just copied Dizzle's answer.

The correct way of doing what dizzle TRIED to do:

For y = a*x^2 + b*x + c, the vertex occurs when x = - b / (2*a)

y=18x^2+9x+14

a = 18
b = 9

- b / (2*a) = - (9) / (2*18) = - 9 / 36 = - 1/4

Take that value for x, evaluate function at that value to get y.
=======================================...
Was so giddy about dizzle's faux pas that I originally did this work. May as well share it:

x-intercept(s) can be found by setting function equal to zero and solving:

y = 18(x + 1/4)^2 + 103/8

0 = 18(x + 1/4)^2 + 103/8

18(x + 1/4)^2 = - 103/8

(x + 1/4)^2 = - 103/144

x + 1/4 = +/- i*sqrt(103)/12

x = - 1/4 +/- i*sqrt(103)/12 OR x = [- 3 +/- i*sqrt(103)] / 12

These are the roots of the equation f(x) = 0

Since the roots are complex, there are no x-intercepts. The function is entirely above the x-axis. </span>
8 0
3 years ago
Read 2 more answers
Pls help me guys i have no idea what im doing...
Lostsunrise [7]

90 + x + 3x = 180

4x = 90

x = 22.5

Your answer: 22.5

7 0
3 years ago
Anderson won $10000 in a Lotto competition.
kozerog [31]

Answer:

jimmy got 30,000

Step-by-step explanation:

10,000

the wife got 60% = 60,000

jimmy got 3x prince = 30,000

prince = 10,000

8 0
3 years ago
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