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statuscvo [17]
3 years ago
13

Which expression is equivalent to 60 - 3y - 9?

Mathematics
2 answers:
disa [49]3 years ago
7 0

Answer:

the answer has to be 3(17-y)

Step-by-step explanation:

I'm pretty sure about that cause what I did at first is subtract the numbers.

<em>6</em><em>0</em><em>-3y-9</em>

=51-3y

factor our 3 from the expression.

3(17-y)

bogdanovich [222]3 years ago
6 0

Answer:

option A

Step-by-step explanation:

the expression given is equal 60-3y-9= -3y+51

The option A doing the distributive property will give you the same answer

3(17) and 3(-Y) = 51 - 3y

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Please help! I feel like I'm drowning :(
algol13

Answer:

1d = -3

2b = 2

2c = 1

3a = 3

3d = 4

Step-by-step explanation:

Polynomial 1: x^2-8x+15

Multiply the leading coefficient, 1, and the last term, 15. You get: 15.

Then, list out the factors of 15 and the addends of -8 until you get two of numbers that are the same:

Factors of 15: -5 * -3

Addends of -8: -5 + -3

Replace the -8x with -5x - 3x:

x^2-5x-3x+15

Put parentheses around the first 2 terms & last 2 terms and factor like so:

(x^2-5x)-(3x+15)

x(x-5)-3(x-5)

(x-5)(x-3)

Looking at the answer (ax + b)(cx + d), d would correspond with -3.

Polynomial 2: 2x^3-8x^2-24x

First factor out the x:

x(2x^{2}-8x-24)

Divide the polynomial inside by 2 and place the 2 outside with the x:

2x(x^2-4x-12)

Then find the factors of 1*-12 and the addends of -4 and see which two numbers match:

Factors of -12: -6 * 2

Addends of -4: -6 + 2

Replace the -8x with -6x + 2x:

2x(x^2-6x+2x-12)

Put parentheses around the first 2 terms & last 2 terms and factor like so:

2x((x^2-6x)+(2x-12))

2x(x(x-6)+2(x-6))

2x((x+2)(x-6))

2x(x+2)(x-6)

Looking at the answer (2x)(ax + b)(cx + d), b & c would correspond with 2 & 1.

Polynomial 3: 6x^2+14x+4

Divide the polynomial by 2:

(2)(3x^2+7x+2)

Find the factors of 3*2 and the addends of 7 and see which two numbers match:

Factors of 6: 6 * 1

Addends of 7: 6 + 1

Replace the 7x with 6x + x:

(2)(3x^2+6x+x+2)

Put parentheses around the first 2 terms & last 2 terms and factor like so:

(2)((3x^2+6x)+(x+2))

(2)(3x(x+2)+(x+2))

(2)((3x+1)(x+2))

(2)(3x+1)(x+2)

Then multiply the 2 with the (x+2) and here's your final answer:

(3x+1)(2x+4))

Looking at the answer (ax + b)(cx + d), a & d correspond with 3 & 4.

Hope that helps (●'◡'●)

(This took a while to write, sorry about that)

8 0
3 years ago
Divisibilty by 2 5 and 10​
Nataly_w [17]

Step-by-step explanation:

if the number ends in a 0,it is divisible by 10.Also if number and s divisible by 2 and 5 it is divisible by 10

6 0
4 years ago
The combined area of two squares is 45 square centimeter each side of one square is twice as long as the side of another square
Roman55 [17]

Let x be the side length of the small square. Then, the side length of the big square is 2x.

The respective areas are x^2 and (2x)^2=4x^2

So, the sum of the areas are x^2+4x^2=5x^2

We have

5x^2=45 \iff x^2=9 \iff x=\pm 3

We can't have negative lengts, so we choose x=3

So, the side length of the larger square is 6.

8 0
3 years ago
What percent of 300 is 67?
Sav [38]
The answer would be 22.33 hope this helped
3 0
4 years ago
Read 2 more answers
a number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and1. How ma
NeX [460]

Answer:

There is NO solution

Step-by-step explanation:

Considering 'y' be the number

Considering x be the smaller number

As 'y' is equal to twice a smaller number plus 3.

so

y = 2x + 3

also

y is equal to twice the sum of the smaller number and 1.

so

y = 2x + 1

so the system of equations become

y = 2x + 3

y = 2x + 1

solving

\begin{bmatrix}y=2x+3\\ y=2x+1\end{bmatrix}

\mathrm{Subsititute\:}y=2x+1

\begin{bmatrix}2x+1=2x+3\end{bmatrix}

\mathrm{Refine\:}2x+1=2x+3

-2=0

-2=0\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}

\mathrm{No\:Solution}

Therefore, there is NO solution.

7 0
3 years ago
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