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3 years ago

The set of all points in a plane that are equidistant from two points is a (n):

1 answer:

7 0

A point is equidistant from other points if the line segments linking to them are congruent(same length) If you any of three points not how one always stays the same distance (equidistant) from the other two.

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Find the remainder when f(x) = 2x3 − 5x2 + 8x + 4 is divided by 2x − 1, and use it to determine if 2x − 1 is a factor.

inysia [295]

Answer:

7; not a factor

Step-by-step explanation:

2x³ - x² - 4x² + 2x + 6x - 3 + 7

x²(2x-1) - 2x(2x-1) + 3(2x-1) + 7

7 is the remainder.

Hence, not a factor

7 0

3 years ago

HELP FAST 34 POINTS AND BRAINLIEST!!

mezya [45]

Answer:

Red: 1/2

White: 1/6

Blue: 1/3

Step-by-step explanation:

You take and find the total number of marbles, which is 18. You then take the number of each different color and make that number your numerator, and 18 your denominator and reduce.

Red: 9/18 reduces to 1/2

White: 3/18 reduces to 1/6

Blue: 6/18 reduces to 1/3

8 0

2 years ago

A chi-square test for independence is being used to evaluate the relationship between two variables, one of which is classified

AysviL [449]

Answer:

Degrees of freedom for independence in chi-square statistic

ν = ( r-1) (s-1) =6

Step-by-step explanation:

Explanation:-

Given data chi-square test for independence is being used to evaluate the relationship between two variables

Given "A" is classified into 3 categories

Second 'B' is classified into 4 categories

In this chi-square test, we test if two attributes A and B under consideration are independent or not

We will assume that

Null Hypothesis : H₀: The two variables are independent

Degrees of freedom in chi-square test for independence

ν = ( r-1) (s-1)

Given data 'r' = 3 and 's' = 4

Degrees of freedom for independence

ν = ( r-1) (s-1) = ( 3-1) ( 4-1) = 2×3 =6

Test statistic

χ ² = ∑ $\frac{(O-E)^{2} }{E}$

4 0

3 years ago

Mackin Investing charges its customers a 1% commission. The Ross Group, a discount broker, charges $25 per trade. For what amoun

olchik [2.2K]

Answer:

The amount of stock for which both brokers would charge the same commission is $2500.

Step-by-step explanation:

i) Let the amount of stock to be traded be worth $x

ii) therefore for both the brokers to charge the same commission we can write

1% of x = $25 $\RIghtarrow$ $\Rightarrow$ 0.01 $\times$ x = 25 $\therefore$ x = $\frac{25}{0.01} = 2500$

The amount of stock for which both brokers would charge the same commission is $2500.

5 0

3 years ago

Minimum Average Cost

Dahasolnce [82]

Answer:

a) $\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}$

b) $\bar{C}(x)=5.81$

Step-by-step explanation:

Given that

C = 100 + 25 x - 120 ln x ,x ≥ 1.

The average cost function given as

$\bar{C}(x)=\dfrac{C(x)}{x}$

$\bar{C}(x)=\dfrac{100 + 25 x - 120 \ln x}{x}$

$\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx{x}$

Therefore

$\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}$

To find average minimum cost

$\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}$

$\dfrac{d\bar{C}(x)}{dx} = -\dfrac{100}{x^2} +0-120\times \dfrac{1-lnx}{x^2}$

$0 = -\dfrac{100}{x^2} +0- 120\times \dfrac{1-lnx}{x^2}$

100 + 120 (1-lnx) = 0

$lnx=\dfrac{220}{120}$

ln x =1.833

$x=e^{1.833}$

x=6.25

$\bar{C}(x)=\dfrac{100}{6.25}+25-120\dfrac{ln6.25}{6.25}$

$\bar{C}(x)=5.81$

6 0

4 years ago